Answer:
the value of 
such that there is no solution to the equation is 
.
Step-by-step explanation:
Let first simplify the expression presented on statement. The equation has no solution if and only if is eliminated in the process and an absurd is the result (i.e. 
).
To obtain an absurd, we need that 
. Hence, the value of such that there is no solution to the equation is:
Let prove the certainty of the result. We find that an absurd exist: ()
Answer:
46
Step-by-step explanation:
5x = 3x - 2 + 34
5x = 3x + 32
2x = 32
x = 16
plug back in
3( 16 ) - 2
48 - 2
46
F = t ⇨ df = dt
dg = sec² 2t dt ⇨ g = (1/2) tan 2t
⇔
integral of t sec² 2t dt = (1/2) t tan 2t - (1/2) integral of tan 2t dt
u = 2t ⇨ du = 2 dt
As integral of tan u = - ln (cos (u)), you get :
integral of t sec² 2t dt = (1/4) ln (cos (u)) + (1/2) t tan 2t + constant
integral of t sec² 2t dt = (1/2) t tan 2t + (1/4) ln (cos (2t)) + constant
integral of t sec² 2t dt = (1/4) (2t tan 2t + ln (cos (2t))) + constant ⇦ answer
We can rewrite the expression under the radical as
then taking the fourth root, we get
![\sqrt[4]{\left(\dfrac32a^2b^3c^4\right)^4}=\left|\dfrac32a^2b^3c^4\right|](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%5Cleft%28%5Cdfrac32a%5E2b%5E3c%5E4%5Cright%29%5E4%7D%3D%5Cleft%7C%5Cdfrac32a%5E2b%5E3c%5E4%5Cright%7C)
Why the absolute value? It's for the same reason that
since both 
and 
return the same number , and 
captures both possibilities. From here, we have
The absolute values disappear on all but the 
term because all of 
, 
and 
are positive, while 
could potentially be negative. So we end up with
3x + 5 = 20
x = 5
Hope this helps
