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Maksim231197 [3]
4 years ago
14

Factorise fully48 + 6x please do quick it's due In 2 min ​

Mathematics
2 answers:
zvonat [6]4 years ago
7 0

Answer:

6(8+x)

Step-by-step explanation:

Notice that the constant and the coefficient have a greatest common factor of 6. Therefore, we can just factor the 6 out to get 6(8+x).

Tresset [83]4 years ago
3 0

Answer:

<h2>6(x+8)</h2>

Step-by-step explanation:

48 + 6x\\\\\mathrm{Rewrite\:}48\mathrm{\:as\:}6\times\:8\\\\=6x+6\times\:8\\\\\mathrm{Factor\:out\:common\:term\:}6\\\\=6\left(x+8\right)

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Luke went fishing and caught a trout that
Elden [556K]

Answer:

40 ounces

Step-by-step explanation:

a pound is 16 ounces so 2 and a half is 40 ounces

8 0
3 years ago
A 5-card hand is dealt from a perfectly shuffled deck. Define the events: A: the hand is a four of a kind (all four cards of one
TiliK225 [7]

In a hand of 5 cards, you want 4 of them to be of the same rank, and the fifth can be any of the remaining 48 cards. So if the rank of the 4-of-a-kind is fixed, there are \binom44\binom{48}1=48 possible hands. To account for any choice of rank, we choose 1 of the 13 possible ranks and multiply this count by \binom{13}1=13. So there are 624 possible hands containing a 4-of-a-kind. Hence A occurs with probability

\dfrac{\binom{13}1\binom44\binom{48}1}{\binom{52}5}=\dfrac{624}{2,598,960}\approx0.00024

There are 4 aces in the deck. If exactly 1 occurs in the hand, the remaining 4 cards can be any of the remaining 48 non-ace cards, contributing \binom41\binom{48}4=778,320 possible hands. Exactly 2 aces are drawn in \binom42\binom{48}3=103,776 hands. And so on. This gives a total of

\displaystyle\sum_{a=1}^4\binom4a\binom{48}{5-a}=886,656

possible hands containing at least 1 ace, and hence B occurs with probability

\dfrac{\sum\limits_{a=1}^4\binom4a\binom{48}{5-a}}{\binom{52}5}=\dfrac{18,472}{54,145}\approx0.3412

The product of these probability is approximately 0.000082.

A and B are independent if the probability of both events occurring simultaneously is the same as the above probability, i.e. P(A\cap B)=P(A)P(B). This happens if

  • the hand has 4 aces and 1 non-ace, or
  • the hand has a non-ace 4-of-a-kind and 1 ace

The above "sub-events" are mutually exclusive and share no overlap. There are 48 possible non-aces to choose from, so the first sub-event consists of 48 possible hands. There are 12 non-ace 4-of-a-kinds and 4 choices of ace for the fifth card, so the second sub-event has a total of 12*4 = 48 possible hands. So A\cap B consists of 96 possible hands, which occurs with probability

\dfrac{96}{\binom{52}5}\approx0.0000369

and so the events A and B are NOT independent.

4 0
3 years ago
i need the answer no playing around please and if the answer is right i will give you a thanks and full stars pleaseeeee
MrRa [10]

Answer:

50+50x

Step-by-step explanation:

they're asking you to use distributive property

so what you have to do is multiply everything that is in the parenthesis by 10

5x10=50

5x10x=50x

so the answer is 50+50x

have a great day :D

7 0
3 years ago
Read 2 more answers
Identify the three similar triangles in the figure. Be sure to name the vertices in the correct order
Sonja [21]

Answer:

BDC  and ADB

Step-by-step explanation:

6 0
2 years ago
Dina planted a six-foot tree in her backyard which she expects to grow at the rate of 4 feet per year. Find the equation of the
Scrat [10]

Answer:

y = 6 + 4x

After 4 years, the tree would be 22 ft tall.

Step-by-step explanation:

Hi there!

Let x = the number of years that pass

Let y = the height of the tree (ft)

We're given that the 6-foot tree grows at a rate of 4 ft per year. This means that the height of the tree will be equal to 6 ft, the original height, plus another 4 ft every year that passes.

Height of tree = 6 feet + 4 feet × number of years that pass

y = 6 + 4x

To solve for how tall the tree would be 4 years after Dina plants it, replace x with 4, since 4 years have passed:

y = 6 + 4(4)

y = 6 + 16

y = 22

Therefore, the tree would be 22 ft tall.

I hope this helps!

8 0
3 years ago
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