Sub x = 2-y^2 to Q, we get:
Q = 3(2-y^2)*y^2
let y^2 = k
Q = 3(2-k)k = 3(2k-k^2)
2k-k^2 has a max when k = 1
Then y^2 = 1 -> y = 1 or -1
Answer:
6√10
Step-by-step explanation:
factorizing 6 and 60
6 = 2 x 3
60 = 2 x 2 x 3 x 5
hence
√6 · √60
= √ [ (2 x 3) · (2 x 2 x 3 x 5) ]
= √ (2· 2² · 3² · 5)
= √ (2² · 3²) x √(2·5)
= (2 · 3) x √10
= 6√10
We have to basically multiply:
11/17 x 475
And simplifying that we get
307.35
And since there can't be .35 person
So out final answer is 307
pls pls brainlist
Answer:
(-65)/17
Step-by-step explanation:
Evaluate 3/(x - 2) - sqrt(x - 3) where x = 19:
3/(x - 2) - sqrt(x - 3) = 3/(19 - 2) - sqrt(19 - 3)
19 - 3 = 16:
3/(19 - 2) - sqrt(16)
19 - 2 = 17:
3/17 - sqrt(16)
sqrt(16) = sqrt(2^4) = 2^2:
3/17 - 2^2
2^2 = 4:
3/17 - 4
Put 3/17 - 4 over the common denominator 17. 3/17 - 4 = 3/17 + (17 (-4))/17:
3/17 - (4×17)/17
17 (-4) = -68:
3/17 + (-68)/17
3/17 - 68/17 = (3 - 68)/17:
(3 - 68)/17
3 - 68 = -65:
Answer: (-65)/17
