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motikmotik
4 years ago
9

At wet pets, a starter tree aquarium kit cost $15 plus $.60 per fish. At grips and frills, the same kit is $13 plus $.80 per fis

h. Give an equation for the cost c of fish at each store.
Mathematics
1 answer:
Katena32 [7]4 years ago
5 0

Answer:

The answer to your question is below

Step-by-step explanation:

Write an equation for the cost of fish at each fish store.

a) Wet pets

We must consider the initial price and the cost of each fish.

total cost = C

kit cost = $15

cost of each fish = $0.60                      

cost of one fish = f

                                C =  15 + 0.60f

Example, if the number of fish is 4, then the total cost will be

                                 C = 15 + 0.60(4)

                                 C = 15 + 2.4

                                 C = $ 17.4                      

b) Grips and Frills

total cost = C

kit cost = $13

cost per fish = $0.80

cost of one fish = f

Equation

                              C = 13 + 0.8f        

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Natalka [10]

Answer:

(29.14 ; 30.06)

Step-by-step explanation:

Given that'

Sample size (n) = 57

Mean (m) = 29.6

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= (1 - 0.8) / 2 = 0.1

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Using the Z probability calculator : Z0. 1 = 1.28

Hence,

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29.6 - (1.28 * 0.3576237) ; 29.6 + (1.28 * 0.3576237)

29.142241664 ; 30.057758336

(29.14 ; 30.06)

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3 years ago
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well then therefore

\stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{3\implies \cfrac{3}{1}} ~\hfill \stackrel{reciprocal}{\cfrac{1}{3}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{1}{3}}}

so we're really looking for the equation of a line with slope of -1/3 and that passes through (1, -3 )

(\stackrel{x_1}{1}~,~\stackrel{y_1}{-3})\qquad \qquad \stackrel{slope}{m}\implies -\cfrac{1}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-3)}=\stackrel{m}{-\cfrac{1}{3}}(x-\stackrel{x_1}{1})\implies y+3=-\cfrac{1}{3}x+\cfrac{1}{3} \\\\\\ y=-\cfrac{1}{3}x+\cfrac{1}{3}-3\implies y=-\cfrac{1}{3}x-\cfrac{8}{3}

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