123 is more than 1 because it is positive and 123 is also positive so the farther away from 0 is greater on the positive side and less on the negative side
X/2 +3y = 6 . . . . . . . . starting point
x/2 = 6 -3y . . . . . . . . subtract terms that don't have x
x = 2(6 -3y) . . . . . . . . multiply by the inverse of the x-coefficient
x = 12 -6y . . . . . . . . . expand if you like
3y = 6 -x/2 . . . . . . . . subtract terms that don't have y
y = (6 -x/2)/3 . . . . . . . multiply by the inverse of the y-coefficient
y = 2 -x/6 . . . . . . . . . expand if you like
40÷5= 8 You have to see how many time 5 can go into 40
1. see how many times 5 goes into 4 none so the first number is 0
2. then you see how many time 5 can go into 0 o times
3. so you have to see how many time you can count 5 into 40
(count by 5's) 5,10,15,20,25,30,35,40 that should be 8 times total!
Answer:
Step-by-step explanation:
An undefined slope is a vertical line on a graph. This means it isn't equal to a y-value, but rather an x-value instead. All values of y work for this function, just as long as the x-coordinate is 11.
