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3 years ago

State the domain of the function.

1 answer:

6 0

Hi there! The domain of a function refers to the values that can be validly input for x. In laymen's terms, domain is the x-values that exist on a graph of the equation.

If we were to plug in y=-2x+5 into a calculator that shows an infinite graph, we would see that the line of the equation would extend both ways infinitely! This means that all real numbers can be inputs for x, because for every x value that exists there is a corresponding y value.

This means that D. All real numbers, is your answer.

Hope it helps! :)

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Step-by-step explanation:

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2 years ago

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Which expressions are equivalent to 10 over 10 3/4?

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There are no choices, but $\frac{10}{10.75}$ can be changes in the following ways: multiplying the numerator and the denominator by the same amount, or dividing the numerator and denominator by the same amount.

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3 years ago

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AC=(5x+12) and BD =8x? Can somebody help me to slove it

AleksAgata [21]

To solve this equation from the information given above, I ordered it 5x+12=8x. To solve, I subtracted 5x from each side, canceling the 5x to your left, leaving only the number 12. 8x minus 5x equals 3x. Take 3x and divide on both sides. 3x/3x cancels the 3, leaving 12/3 equals 4. Finally, x equals 4.

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3 years ago

15. Challenge! Find the surface area of the figure below.

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Is it 25 cm???????.................

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3 years ago

7) PG & E have 12 linemen working Tuesdays in Placer County. They work in groups of 8. How many

BabaBlast [244]

Part A

Since order matters, we use the nPr permutation formula

We use n = 12 and r = 8

$_{n}P_{r} = \frac{n!}{(n-r)!}\\\\_{12}P_{8} = \frac{12!}{(12-8)!}\\\\_{12}P_{8} = \frac{12!}{4!}\\\\_{12}P_{8} = \frac{12*11*10*9*8*7*6*5*4*3*2*1}{4*3*2*1}\\\\_{12}P_{8} = \frac{479,001,600}{24}\\\\_{12}P_{8} = 19,958,400\\\\$

There are a little under 20 million different permutations.

<h3>Answer: 19,958,400</h3>

Side note: your teacher may not want you to type in the commas

============================================================

Part B

In this case, order doesn't matter. We could use the nCr combination formula like so.

$_{n}C_{r} = \frac{n!}{r!(n-r)!}\\\\_{12}C_{8} = \frac{12!}{8!(12-8)!}\\\\_{12}C_{8} = \frac{12!}{4!}\\\\_{12}C_{8} = \frac{12*11*10*9*8!}{8!*4!}\\\\_{12}C_{8} = \frac{12*11*10*9}{4!} \ \text{ ... pair of 8! terms cancel}\\\\_{12}C_{8} = \frac{12*11*10*9}{4*3*2*1}\\\\_{12}C_{8} = \frac{11880}{24}\\\\_{12}C_{8} = 495\\\\$

We have a much smaller number compared to last time because order isn't important. Consider a group of 3 people {A,B,C} and this group is identical to {C,B,A}. This idea applies to groups of any number.

-----------------

Another way we can compute the answer is to use the result from part A.

Recall that:

nCr = (nPr)/(r!)

If we know the permutation value, we simply divide by r! to get the combination value. In this case, we divide by r! = 8! = 8*7*6*5*4*3*2*1 = 40,320

So,

$_{n}C_{r} = \frac{_{n}P_{r}}{r!}\\\\_{12}C_{8} = \frac{_{12}P_{8}}{8!}\\\\_{12}C_{8} = \frac{19,958,400}{40,320}\\\\_{12}C_{8} = 495\\\\$

Not only is this shortcut fairly handy, but it's also interesting to see how the concepts of combinations and permutations connect to one another.

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<h3>Answer: 495</h3>

5 0

2 years ago