Question

In a parallel circuit, ET = 240 V, R = 47 kΩ, and XL = 50 kΩ. What is the reactive power?

Answer 1

Answer:

Reactive power is 1.152 VARs

Step-by-step explanation:

We are given that in a parallel circuit,$E_{T}=240V$,R=47kΩ and $X_{L}$=50kΩ.

reactive power means the dissipating power resulting from inductive and capacitive loads measured in volt-amperes reactive(VAR).Since our circuit has inductor only, reactive power will be power dissipated from inductor.

Current through inductor=$\frac{E_{T}}{X_{L}} =\frac{240}{50}=4.8$milli amps=0.0048 A

Reactive power = (current flowing through inductor)X (Voltage across inductor)

Hence reactive power = 0.0048 X 240=1.152 VARs