All categories

2 years ago

marking brainlist. please help What is the first inverse operation for the following problem? 3x+4=12

Mathematics

1 answer:

Strike441 [17]2 years ago

3 0

Answer:

3x + 4 = 12 :- x = 8 / 3

Step-by-step explanation:

3x + 4 = 12

Move all terms not containing x to the right side of the equation.

Subtract 4 from both sides of the equation.

3x = 12 - 4

Subtract 4 from 12.

3x = 8

Divide each term by 3 and simplify.

Divide each term in 3x = 8 by 3.

3x / 3 = 8 / 3

Cancel the common factor of 3.

Divide x by 1.

x = 8 / 3

The result can be shown in multiple forms.

Exact Form:

x = 8 / 3

Decimal Form:

x = 2.6

Mixed Number Form:

x = 2 2/3

You might be interested in

A vase can hold 9 flowers. If a florist had 878 flowers she wanted to put equally into vases, how many flowers would be in the l

zavuch27 [327]

There are 5 flowers in the last vase because you divide 878 by 9 and get 97 and then you have 5 leftover

3 0

2 years ago

Read 2 more answers

How do you divide 3.36/1.4?

ahrayia [7]

Answer:

move the decimal in 1.4 two places two the right and do the same with 3.36 then divide

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Solve for t. −18=6t What is the answer? −3 −1/3 12 24

Vadim26 [7]

Answer:

t=-3

Step-by-step explanation:

6t=−18

t=-18/6

t=-3

6 0

2 years ago

Read 2 more answers

Help me asap! I will give you marks

Law Incorporation [45]

Recall the binomial theorem.

$(a+b)^n = \displaystyle \sum_{k=0}^n \binom nk a^{n-k} b^k$

1. The binomial expansion of $\left(1+\frac x3\right)^7$ is

$\left(1 + \dfrac x3\right)^7 = \displaystyle\sum_{k=0}^7 \binom 7k 1^{7-k} \left(\frac x3\right)^k = \sum_{k=0}^7 \binom 7k \frac{x^k}{3^k}$

Observe that

$k = 1 \implies \dbinom 71 \left(\dfrac x3\right)^1 = \dfrac73 x$

$k = 2 \implies \dbinom 72 \left(\dfrac x3\right)^2 = \dfrac73 x^2$

When we multiply these by $8-9x$ ,

• $8$ and $\frac73 x^2$ combine to make $\frac{56}3 x^2$

• $-9x$ and $\frac73 x$ combine to make $-\frac{63}3 x^2 = -21x^2$

and the sum of these terms is

$\dfrac{56}3 x^2 - 21x^2 = \boxed{-\dfrac73 x^2}$

2. The binomial expansion is

$\left(2a - \dfrac b2\right)^8 = \displaystyle \sum_{k=0}^8 \binom 8k (2a)^{8-k} \left(-\frac b2\right)^k = \sum_{k=0}^8 \binom 8k 2^{8-2k} a^{8-k} b^k$

We get the $a^6b^2$ term when $k=2$ :

$k=2 \implies \dbinom 82 2^{8-2\cdot2} a^{8-2} b^2 = 28 \cdot2^4 a^6 b^2 = \boxed{448} \, a^6b^2$

6 0

10 months ago

How many time does 2 go into 19

BigorU [14]

Hello There @Diamondinthesky123 (Cute Username)

When you state the question, "How many times does 2 go into 19", I assume your talking about Long Division. (Not so long in this case)

In this case, we would divide 19 by 2, resulting in 9 with a remainder of 1.
Thats It! :)

I hope I helped, Have a great Day!

Thank you,
Darian D.

4 0

3 years ago