Answer:
p = 2 or p = -2 4/9
Step-by-step explanation:
We can substitute x=3/2 into the equation and solve for the values of p that make the result be zero.
p^2(3/2)^2 -12(3/2) +p +7 = 0
9/4p^2 -18 + p + 7 = 0 . . . . eliminate parentheses
9p^2 +4p -44 = 0 . . . . . . simplify and multiply by 4
(9p +22)(p -2) = 0 . . . . . factor
Values of p that make 3/2 be one of the zeros are ...
p = -22/9, p = 2
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<em>Additional comment</em>
The <em>zero product rule</em> tells you a product will be zero if and only if a factor is zero. Hence the solutions to the quadratic are values of p that make the factors zero.
9p +22 = 0 ⇒ 9p = -22 ⇒ p = -22/9
p -2 = 0 ⇒ p = 2
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For p=2, the solution 3/2 has multiplicity 2. For p=-22/9, the other zero is x=123/242.
You'll need to isolate 9a on the left side of this equation
Please add 7 to both sides of the eqn, obtaining 9a = 117.
Solve for a by dividing both sides by 9: a = 117/9 = 13 (answer)
Answer:
L = 15, W = 8
Step-by-step explanation:
Perimeter = 2(L + W)
P = 40
L = 2W - 1
40 = 2((2W-1) + W)
40 = 4W - 2 + 2W
40 = 6W - 2
42 = 6W
W = 8
Since L = 2W - 1
L = 2(8) - 1
L = 15
Answer:
c+6
Step-by-step explanation:
add variable to constant c+6
