10minutes= 10/60 hours
= 1/6 hrs
speed = distance/ time
=3/ (1/6)
= 18 km/h
This looks fun
ok so
we will use subsitution
xy=-10
divide both sides by x or y (I will choose y)
x=-10/y
sub -10/y fo x
(-10/y)^2+y^2=36
100/(y^2)+y^2=36
times both sides by y^2
100+y^4=36y^2
minus 36y^2 from both sides
y^4-36y^2+100=0
(y^2)^2-36(y^2)+100=0
quadratic formula
for
ax^2+bx+c=0
x=

x=

x=

sub
y=-10/x
y=

so x+y=

+

multiply first number by

and add them
x+y=

or
x+y=

or
A can of paint is a cylinder, so we must use the surface area for a cylinder.
2(

r

) is the top and bottom.
The surface of the can is a rectangle with a length equal to the circumference of the can.
Answer:
4 , 24 , 144 , 864 , 5184
This is a sequence which is multiplied by 6 with the new digit.
First: 4
second: 4 * 6 = 24
third: 24 * 6 = 144
fourth: 144 * 6 = 864
fifth: 864* 6 = 5184
sixth: 5184 * 6 = 31104
seventh: 31104 * 6 = 186624
This sequence is never ending. Write the first 5 five in sequence that's the answer.
The percentage of the runners who have times less than 14.4 sec is 0.15%
The times of all 15-year old who run a certain race are approximately normally distributed with a given mean of 18 sec and a standard deviation of 1.2 sec.
We know that,
where,
X = raw score = 14.4
μ = mean = 18
σ = standard deviation = 1.2
Putting the values,
Finding the probability from the z score table, we get
P(z < -3) = 0.00135 = 0.135%
Disclaimer: The question is incomplete. Please read below to find the missing content.
Question: The times of all 15-year-olds who run a certain race are approximately normally distributed with a given mean of 026-1 = 18 seconds and a standard deviation of 026-2. = 1.2 sec. What percentage of the runners have times less than 14.4 seconds?
0.15%
0.15%
0.30%
0.60%
2.50%
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