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never [62]
3 years ago
14

What is the customary unit of a sink

Mathematics
2 answers:
Nata [24]3 years ago
7 0
The customary unit for liquid volume of a sink is gallon 
3241004551 [841]3 years ago
6 0
It would probably be a full whole gallon 
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I have a Brainliest please help
Firdavs [7]
31) ($6 * 2) + $6.25 + $4.25 + $20 = $42.50

32) $50 - $8.25 - $4.25 -$4.25 - $20 = $13.25

33) 6 * 15.99 = 95.94 | $100 - $95.94 = $4.06

34) $10.50 * 8 = 84 | $100 - $84 = $16

Hope this helps! ^^
5 0
3 years ago
What is the volume of this prism?
kkurt [141]
Answer: 126 cubic inches

To find this answer...
All you simply have to do is to plug in the answers to the volume equation (length × width × height = volume)

The length is 6 inches
The width is 3 inches
The height is 7 inches

6×3 is 18
18×7 is 126

Hope this helps!
4 0
4 years ago
What is 45 * 89 + 67 <55 - 56 =
gladu [14]

Answer:

False

Step-by-step explanation:

Use the order of operations

45 * 89 = 4005

4005 + 67 = 4072

55 - 56 = -1

4072 < -1

The answer is false.

4 0
3 years ago
Read 2 more answers
Can two data sets have the same mean but different standard deviations?
agasfer [191]

Yes they can and it depends on what the standard deviations are. The standard deviation is a measure of how close results are to the mean, a low standard deviations means the measurements are precise, so close to the mean. A high standard deviation means that measurements are more spread out.  Saying that one set is more spread out than the other.

5 0
3 years ago
A printer need to make a poster that will have a total poster area of 200 in^2 and will have 1 inch margins on the sides, a 2-in
Katyanochek1 [597]

Answer:

The dimensions that will give the largest printed area of 132.1669 in^2 are

= Length x Width

= 15.20829 * 8.69045

Step-by-step explanation:

a) Data and Calculations:

Total poster area = 200 in^2

Side margins = 1 inch each

Top and bottom margins = 2 inches each

Let x = length of the full poster

then 200/x = width of the full poster

Therefore, the length of the printed area = x - 3.5

and the width of the printed area = (200/x)-2

Therefore, the Area of the Printed space = (x-3.5)((200/x)-2)

Solving for the Area (A) of the printed space, we have

 

A = (x-3.5)(-200/x2) + ((200/x)-2)

 

A = 700 -2x2

 

If the derivative is set to 0, we have:

0 = 700 -2x2

 

700 = 2x2

 

350 = x2

 

x = 18.70829  The original length

 

width = 10.69045

 

Therefore, the area of space available for printing is

 

15.20829  *  8.69045

 

= 132.1669 in^2

5 0
3 years ago
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