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Alik [6]
3 years ago
15

In January Mr Patel's electricity meter reading is 36 517. During the next three months he uses 1 084 units of electricity. a) W

hat is the reading on his meter at the end of these three months? b) In Janurary Mr Patel'a gas meter reading is 51 314. Three months later it is 51 809. How many units of gas has he used? c) Electricity costs 12 pence per unit. Gas costs 8.6 pence per unit. Work out the total cost of Mr Patel's gas and electricity for these three months. Give your answer in pounds.
Mathematics
1 answer:
RUDIKE [14]3 years ago
4 0

Answer: 172.65 pound

Step-by-step explanation:

a. What is the reading on his meter at the end of these three months?

January's electricity meter reading = 36,517.

Electricity used for next three months = 1 084 units

Meter reading at the end of the three months will be:

= 36517 + 1084

= 37601

b. In Janurary Mr Patel'a gas meter reading is 51 314. Three months later it is 51 809. How many units of gas has he used?

This will be:

= 51,809 - 51,314

= 495 units

c. Electricity costs 12 pence per unit. Gas costs 8.6 pence per unit. Work out the total cost of Mr Patel's gas and electricity for these three months.

Electricity used for next three months = 1 084 units

Gas used for next three months

= 495 units

Cost = (1084 × 12pence) + (495 × 8.6 pence)

= 13008 pence + 4257 pence

= 17265 pence = 172.65 pound

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Therefore the maximum value of function f(x,y,z)=x^{2} y^{2} z^{2} =1/27

And the minimum value is 0

<h3>What is function?</h3>

function, in mathematics, an expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable (the dependent variable) (the dependent variable) (the dependent variable) (the dependent variable). Mathematics uses functions frequently, and functions are essential for specifying physical relationships in the sciences.

Here,

The function is given as:

f(x,y,z)=x^{2} y^{2} z^{2}

x^{2} +y^{2}+ z^{2}=1

=>x^{2} +y^{2}+ z^{2}-1=0

Using Lagrange multiplies, we have:

L(x,y,z,λ)=f(x,y,z) +λ(0)

Substitute f(x,y,z)=x^{2} y^{2} z^{2}  and x^{2} +y^{2}+ z^{2}-1=0

Differentiate

L(x)=2xy^{2} z^{2}+2λx

L(y)=2yx^{2} z^{2}+2λy

L(z)=2zx^{2} y^{2}+2λz

L(λ)=x^{2} +y^{2}+ z^{2}-1

Equating to 0

2xy^{2} z^{2}+2λx =0

2yx^{2} z^{2}+2λy = 0

2zx^{2} y^{2}+2λz = 0

x^{2} +y^{2}+ z^{2}-1 = 0

Factorize the above expressions

2xy^{2} z^{2}+2λx =0

2x(y^{2} z^{2}+λ)=0

2x=0 and (y^{2} z^{2}+λ)=0

x=0 and  y^{2} z^{2}= -λ

2yx^{2} z^{2}+2λy = 0

2y(x^{2} z^{2}+λ)=0

2y=0 and (x^{2} z^{2}+λ)=0

y=0 and  x^{2} z^{2}= -λ

2zx^{2} y^{2}+2λz = 0

2z(y^{2} x^{2}+λ)=0

2z=0 and (x^{2} y^{2}+λ)=0

z=0 and  x^{2} y^{2}= -λ

So we have ,

x=0 and  y^{2} z^{2}= -λ

y=0 and  x^{2} z^{2}= -λ

z=0 and  x^{2} y^{2}= -λ

The above expression becomes

x=y=z=0

This means that,

x^{2} +y^{2}+ z^{2}=1

x^{2} +x^{2}+ x^{2} =1 \\3x^{2 } =1

x= ±1/\sqrt{3}

So,

y= ±1/\sqrt{3}

z= ±1/\sqrt{3}

The critic points are

x=y=z=±1/\sqrt{3}

x=y=z=0

Therefore the maximum value of function f(x,y,z)=x^{2} y^{2} z^{2} =1/27

And the minimum value is 0

To know  more about function , visit

brainly.com/question/12426369

#SPJ4

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