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3 years ago

Least common multiple find the least common multiple of each set of numbers 15 and 20

Mathematics

2 answers:

just olya [345]3 years ago

7 0

LCM for 15 and 20 is 60.

Here, let's use 20. Add it by 20 and you'll get 40. 15 is not a multiple of 40, so we add 20 to 40 again. 60 is a multiple of 15.

15 x 4

Hope this helped. =]

enot [183]3 years ago

5 0

Answer: 60

Step-by-step explanation:

multiples of 20: 20, 40, 60, 80 100

multiples of 15: 15, 30, 45, 60, 75

which one is similar?

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The length of the segment indicated round your answer to the nearest 10th if nessesary

exis [7]

Pythagorean Theorem
x^2 = 15.7^2 -7.8^2
x^2 = 185.65 
x = 13.6253440324 
Answer is C

3 0

3 years ago

I am thinking of two numbers. The sum of the two is 10 and the difference is 2

mixer [17]

Answer:

4 and 6

Step-by-step explanation:

First, let's find all the pairs that add up to 10.

1 + 9, 2 + 8, 3 + 7, 4 + 6, and 5 + 5

Next, we find the difference between the addends for each pair.

9 - 1 = 8
8 - 2 = 6
7 - 3 = 4
6 - 4 = 2
5 - 5 = 0

As you can, see the numbers that add to 10 and have a different of 2 is 4 and 6.

5 0

2 years ago

7. Find the perimeter of triangle FGH.

belka [17]

Answer:

9.) Its equilateral

7.) 24

Step-by-step explanation:

Sorry I only have the answer for 7 and 9.

3 0

3 years ago

Please help me anyone

kotykmax [81]

Answer:

Quelles caractéristiques ces mots ont-ils en commun ? Cliquez sur tout ce qui s'applique.

$\left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right]$

Step-by-step explanation:

8 0

3 years ago

A ladder 16 feet long is leaning against the wall of a tall building. The base of the ladder is moving away from the wall at a r

svet-max [94.6K]

Answer:

a. 0.588

b. 0.0722

c. 4.576 sqft/sec

Step-by-step explanation:

Let b and h denote the base and height as indicated in the diagram. By pythagoras theorem, $h^2 + b^2 = 16^2 = 256 \dotsc\;(1)$ because it is a right angle triangle.

It is given that $\frac{db}{dt} = 1$

Now differentiate (1) with respect to t (time) :

$\displaystyle{2h\frac{dh}{dt} + 2b\frac{db}{dt} = 0 \implies \frac{dh}{dt} = -\frac{b}{h} \frac{db}{dt}}$

$\displaystyle{=-\frac{b}{\sqrt{256 - b^2}} \frac{db}{dt} = -\frac{8}{13.856} \times 1 = -0.588}$

The minus sign indicates that the value of h is actually decreasing. The required answer is 0.588.

b. From the diagram, infer that $16 \sin{\theta} = b$ . When b = 8, then $\theta = \arcsin{0.5} = \ang{30}$ .

Differentiate the above equation w.r.t t

$\displaystyle{16 \cos{\theta} \frac{d\theta}{dt} = \frac{db}{dt} \implies \frac{d\theta}{dt} = \frac{1}{16 \cos{\theta}} = \frac{1}{13.856} = \mathbf{0.0722}}$

c. The area of the triangle is given by $A = 0.5\times h \times b$ . Differentiating w.r.t t,

$\displatstyle{\frac{dA}{dt} = 0.5 b \frac{dh}{dt} + 0.5 h \frac{db}{dt}}$

Plugging in b = 8, h = 13.856, $\frac{dh}{dt} = -0.588$ ,

$\frac{dA}{dt} = -2.352 + 6.928 = \mathbf{4.576 ft^2/sec}$

8 0

3 years ago