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2 years ago

I have no idea how to work this problem out and the answer

Mathematics

2 answers:

frutty [35]2 years ago

6 0

Answer:

Photographer B, photographer D, photographer C, photographer A

Step-by-step explanation:

The easiest way to solve this would be to set all of the values to fractions with a common denominator. In this case, it makes the most sense for the denominator to be 100.

Photographer A:

$\frac{2}{5}$ × $\frac{20}{20}$ = $\frac{40}{100}$

Photographer B:

4% = $\frac{4}{100}$

Photographer C:

0.29 = $\frac{29}{100}$

Photographer D:

$\frac{27}{100}$

Now that you have every value set as a fraction with a common denominator, you can easily tell that the order from least to greatest is:

Photographer B, photographer D, photographer C, photographer A

NeTakaya2 years ago

3 0

Answer:

B, D, C, A

Step-by-step explanation:

The question is asking to put the photographers into least to greast.

For the best case, I suggest you change them into decimals and put them in order.

Photgrapher A: 2/5 = 0.4 = 40%

Photographer B: 4% = 0.04 = 4%

Photographer C: 0.29 = 29%

Photographer D: 27/100 = 0.27 = 27%

Now put them into least to greatest.

Photographer B, Photographer D, Photographer C, And Photographer A

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(X^4)-(45x^2)+324 what are the zeroes? And how many turning points?

dmitriy555 [2]

Zeroes:

We must solve

$x^4-45x^2+324=0$

To do so, we define the auxiliary variable $t=x^2$ . The equation becomes

$t^2-45t+324=0$

The quadratic formula yields the solutions

$t=9,\quad t=36$

Substituting back $t=x^2$ gives

$x^2=9 \iff x=\pm 3,\quad x^2=36 \iff x=\pm 6$

So, the zeroes are -6, -3, 3, 6.

Turning points:

Turning points are points where a function stops being increasing to become decreasing, or vice versa. Since functions are increasing when their first derivative is positive and decreasing when it's negative, turning points are points where the first derivative is zero.

We have

$f(x)=x^4-45x^2+324 \implies f'(x)=4x^3-90x$