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gizmo_the_mogwai [7]
3 years ago
15

You own three different rings. You wear all three rings, but no two of the rings are on the same finger, nor are any of them on

your thumbs. In how many ways can you wear your rings? (Assume any ring will fit on any finger.) Explain and prove your answer.
Mathematics
1 answer:
Eddi Din [679]3 years ago
4 0

Answer:

Therefore you can wear your rings in =336 ways

Step-by-step explanation:

Multiplication Law: If one occurs in x ways and second event occurs in y ways.Then the number of ways that two event occur in sequence is xy

Given that you have 3 different rings.

We have total 10 figures.

But you don't wear ring on your thumbs.

We have 2 thumbs.

So you can wear rings on (10-2) = 8 figures.

The ways of wearing of first ring is = 8

The ways of wearing of second ring is = 7

The ways of wearing of third ring is = 6

Therefore you can wear your rings in =(8×7×6)

                                                             =336 ways

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agasfer [191]

<u>Answer:</u>

The system of equations are

x + y = 2600   …….equation (1)

and, 6x + 5y = 13700  ……equation (2)

<u>Explanation:</u>

Let x = amount of sales of phone;

y = amount of sales of computer

For phone, 6% of sales is 6% of x, or 6% * x = 0.06x.

Similarly for computer,

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Given the total sales; x + y = 2600

And commission; 0.06x + 0.05y = 137; or 6x + 5y = 13700

Therefore the system of equations are

x + y = 2600   …….equation (1)

6 x + 5 y = 13700  ……equation (2)

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3 years ago
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alexandr402 [8]

Answer:

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Step-by-step explanation:

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divide all through by 5x

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the greater sign change here

which is x<5

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