Answer:
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(3-(-1))/(-2-4)
m=(3+1)/-6
m=4/-6
simplify
m=-2/3
y-y1=m(x-x1)
y-(-1)=-2/3(x-4)
y+1=-2/3(x-4)
y+1=-2/3x+8/3
y=-2/3x+8/3-1
y=-2/3x+8/3-3/3
y=-2/3x+5/3
y-(-2/3x)=5/3
y+2/3x=5/3
2/3x+y=5/3
3(2/3x+y)=3(5/3)
2x+3y=5
2x+3y-5=0
The first and the third option are correct. if you fail to do the second and last they will take away your house lol
<h3>
Answer: 10^(1/2)</h3>
When we use an exponent of 1/2, it is the same as a square root. The more general rule is

In this case, we plug in x = 10.
The use of a fractional exponent is handy when you want to deal with things like cube roots on a calculator. This is because
![\sqrt[3]{x} = x^{1/3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%7D%20%3D%20x%5E%7B1%2F3%7D)
Many calculators don't have a button labeled
but they have the button
to allow fractional exponents.
Answer:
here's the answer
Step-by-step explanation:
hope this helps!