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mylen [45]
2 years ago
6

What is b over 7 when b= 14

Mathematics
2 answers:
Drupady [299]2 years ago
8 0
The answer is 2 because 14/7 equals 2.
Anit [1.1K]2 years ago
7 0

If we have the expression \frac{b}{7}, substitute 14 for b to simplify.

\frac{b}{7} → \frac{14}{7} → 2

The complete simplified expression is 2.

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In Brownsville Texas it is 80°F the temperature is expected to drop 1.5° each hour in Mesquite Texas is 94°F and the temperature
denis-greek [22]

Answer:

28 hours

Step-by-step explanation:

let the time period at which the temperature be equal in both Brownsville and Mesquite Texas be 'x'.

Given,

In Brownsville Texas, the temperature is expected to drop 1.5° each hour and In Mesquite Texas, the temperature is expected to drop 2° each hour.

Now, according to the question,

after 'x' hours,

⇒ 80° - 1.5°(x) = 94° - 2°(x)

⇒ 0.5°(x) = 14°

⇒ x = 28

Hence, Till 28 more hours the temperature in Mesquite Texas be greater than that in Brownsville.

3 0
3 years ago
Look at the pattern below.
jonny [76]

Answer:

21 squares

Step-by-step explanation:

6+5+4+3+2+1=21

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cboxed%7B%5Cboxed%7B%20%5Cbegin%7Barray%7D%7B%7D%5Clarge%5Ctt%20The%20%20%5C%5C%20%20%5Ct
larisa86 [58]

Distance formula

\boxed{\sf \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}

Now

#1

\\ \tt\Rrightarrow AB=\sqrt{(3-3)^2+(-2-8)^2}=\sqrt{100}=10units

#2

\\ \tt\Rrightarrow OK=\sqrt{(5-7)^2+(-2+2)^2}=\sqrt{4}=2units

#3

\\ \tt\Rrightarrow LM=\sqrt{(-4-4)^2+(6+4)^2}=\sqrt{64+100}=\sqrt{164}\approx 13units

#4

\\ \tt\Rrightarrow PC=\sqrt{(5-2)^2+(1-3)^2}=\sqrt{9+4}=\sqrt{13}=3.2units

#5

\\ \tt\Rrightarrow QR=\sqrt{(-2+10)^2+(3-9)^2}=\sqrt{64+36}=\sqrt{100}=10units

8 0
2 years ago
Read 2 more answers
Arrange these numbers from least to greatest 2/5 5/7 4/9
mr Goodwill [35]
4/9 2/5 5/7 is sorted from least to greatest

4 0
2 years ago
Read 2 more answers
1. A set of weights includes a 5 lb barbell and 8 pairs of weight plates. Each pair, p,
lidiya [134]

Answer:

5 <= y <= 85

Step-by-step explanation:

Since the lowest weight possible is 5lbs (just the barbell and no weights) the lowest point of the range is 5lbs (the y intercept when x = 0)

The highest weight possible is 85lbs since, there is only 8 pairs of weight plates (8 is the input value) and the pairs each weigh 10lbs (the slope of the graph) + 5lbs from the barbell (y-intercept).

Using the function given, if you input 8 as the x value, you get

85 = 10(8) + 5

So the highest value of the range is 85lbs, therefore the range is 5 <= y <= 85.  

6 0
3 years ago
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