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alexandr402 [8]
4 years ago
9

What is the formula for the following arithmetic sequence? 12, 6, 0, -6, ...

Mathematics
2 answers:
bixtya [17]4 years ago
6 0

Answer:

an= 12 + (-6)(n-1)

Step-by-step explanation:

you should find two values: a1 and d

a1= first number =12

d= a number of the sequence mines the number of the sequence before the one you chose = 0-6 = -6

a1+(n-1)d= 12-6(n-1)

mina [271]4 years ago
3 0

Answer:

12 + (-6)(n-1)

Hope it helped <3

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Likurg_2 [28]

Answer:

5^-5

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
P(x)=Third-degree, with zeros of −3, −1, and 2, and passes through the point (1,12).
Mila [183]

Answer:

The polynomial is:

p(x) = -x^3 - 2x^2 + 5x + 6

Step-by-step explanation:

Zeros of a function:

Given a polynomial f(x), this polynomial has roots x_{1}, x_{2}, x_{n} such that it can be written as: a(x - x_{1})*(x - x_{2})*...*(x-x_n), in which a is the leading coefficient.

Zeros of −3, −1, and 2

This means that x_1 = -3, x_2 = -1, x_3 = 2. Thus

p(x) = a(x - x_{1})*(x - x_{2})*(x-x_3)

p(x) = a(x - (-3))*(x - (-1))*(x-2)

p(x) = a(x+3)(x+1)(x-2)

p(x) = a(x^2+4x+3)(x-2)

p(x) = a(x^3+2x^2-5x-6)

Passes through the point (1,12).

This means that when x = 1, p(x) = 12. We use this to find a.

12 = a(1 + 2 - 5 - 6)

-12a = 12

a = -\frac{12}{12}

a = -1

Thus

p(x) = -(x^3+2x^2-5x-6)

p(x) = -x^3 - 2x^2 + 5x + 6

6 0
3 years ago
What is the circumference of a circle that's radius is 4​
inessss [21]

Answer:

The circumference is 25.13

Step-by-step explanation:

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3 years ago
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vredina [299]

Answer:


Step-by-step explanation:

Note that the quadratic formula has that "plus or minus" due to our taking the square root of some quantity.  No square root is involved in the two formulas you've posed.

I have two suggestions here:

1) Write " (x plus or minus y)^2 = x^ plus or minus 2 times xy + y^2 "  Note that a + on the left side corresponds to a + on the right side, and same with - .

2) Memorize these two formulas, which in most algebra textbooks you'll find in the section "special products and factoring."


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3 years ago
Hi i need help on segment relationships in circles
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