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topjm [15]
3 years ago
6

There are 3 drama movies 8 comedy movies and 4 action movies what's the ratio of dramas to movies ?

Mathematics
2 answers:
IRISSAK [1]3 years ago
7 0
3:12 or 1:4 write both and ask which one is better to use
lora16 [44]3 years ago
5 0
3:15, 3/15, or 3 to 15.

How I got that was add all of the 3 types of movies together. 3+8+4= 15. And there are 3 drama movies. So I looked at "the ratio of DRAMA, to MOVIES.", and I wrote down what was first. 

I'm not sure if I made sense, sorry. But 
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Marcus has $28 to spend. He spent $3.75 to buy a notebook. He needs to save $11.25 but he wants to buy a snack. Chips cost $1.30
Alborosie

Total money Marcus has = $28

Money spent to buy a notebook = $3.75

Money left now = 28-3.75=24.25

Money needed to be saved = $11.25

So, the amount of money Marcus can spend = 24.25-11.25=13

Cost of a packet of chips = $1.30

The inequality to determine the maximum number of chips he can buy is:

Let the number of chips Marcus can buy = x

As he cannot spend more than $13 to buy chips so equation becomes:

1.30x\leq 13

Solving this we get

x\leq 10

Hence, Marcus can buy a maximum of 10 packs of chips and  save $11.25



4 0
3 years ago
35-x= -10<br><br> Please help
wlad13 [49]

Answer:

35-x= -10

X= 45

4 0
3 years ago
Read 2 more answers
Please answer question three and four if you can :)<br> Show full working out ty;)
nikklg [1K]

Step-by-step explanation:

3

Let D be the mid point of side BC, [B(2, - 1), C(5, 2)].

Therefore, by mid-point formula:

D = ( \frac{2 + 5}{2},  \:  \:  \frac{ - 1 + 2}{2} ) = ( \frac{7}{2}, \:  \:  \frac{ 1}{2} ) \\ \therefore D= (3.5, \:  \: 0.5) \\  \& \: A=(-1,\:\:4)...(given) \\\\  now \: by \: distance \: formula \\  \\ Length  \: of \:  segment  \: AD \\  =  \sqrt{( - 1 - 3.5)^{2}  +  {(4 - 0.5)}^{2} }  \\ =  \sqrt{(4.5)^{2}  +  {(3.5)}^{2} }  \\ =  \sqrt{20.25 + 12.25 }  \\  =  \sqrt{32.5}  \\    \red{ \boxed{\therefore Length  \: of \:  segment  \: AD  = 5.7 \: units}}

4 (a)

Equation of line AB[A(2, 1), B(-2, - 11)] in two point form is given as:

\frac{y-y_1}{y_1-y_2} =\frac{x-x_1}{x_1 - x_2} \\\\\therefore \frac{y-1}{1-(-11)} =\frac{x-2}{2 - (-2) } \\\\\therefore \frac{y-1}{1+11} =\frac{x-2}{2 +2} \\\\\therefore \frac{y-1}{12} =\frac{x-2}{4} \\\\\therefore \frac{y-1}{3} =\frac{x-2}{1} \\\\\therefore y-1= 3(x - 2)\\\\\therefore y= 3x - 6+1\\\\\therefore y= 3x - 5\\\\ \huge \purple {\boxed {\therefore 3x - y-5=0}} \\

is the equation of line AB.

Now we have to check whether C(4, 7) lie on line AB or not.

Let us substitute x = 4 & y = 7 on the Left hand side of equation of line AB and if it gives us 0, then C lies on the line.

LHS = 3x - y-5\\=3\times 4-7-5\\= 12-12\\=0\\= RHS

Hence, point C (4, 7) lie on the straight line AB.

4(b)

Like we did in 4(a), first find the equation of line AB and then substitute the coordinates of point C in equation and if they satisfy the equation, then all the three points lie on the straight line.

4 0
3 years ago
the value of a baseball card can be represented by the equation y equals 3x + 39 where X represents the number of years that Rob
Blababa [14]

Answer:

I need the values of either X or Y to solve this. I can solve for what X is though.

Step-by-step explanation:

A: X = -12

B: X =78

C: X = 12.13

I hope this helps you, but since both X and Y are unknown variables, you can't solve it, only simplify (which it already is.)

3 0
3 years ago
Jeri drew the following model to represent the fraction. What's wrong with her model?
Shtirlitz [24]

Answer: were is the model

6 0
3 years ago
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