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ASHA 777 [7]
3 years ago
8

Write an equation, in slope-intercept form using the given info. (5, 4) m= -2/3

Mathematics
1 answer:
ELEN [110]3 years ago
8 0

Answer:

y = -2/3x + 22/3

Step-by-step explanation:

An equation is written in slope-intercept form when it is written as:

y = mx + b, where m is the slope of the line and b is the y-intercept.

Therefore, because we are given m and a coordinate pair of the line, we can use the point-slope formula to make the equation.

The point-slope formula is \boxed{y-y_{1}=m(x-x_{1})}.

Because we are given only one coordinate pair, it is labeled as (x_{1}, y_{1}).

Now, just plug in this information and solve the equation.

y - 4 = -2/3(x - 5) Distribute the -2/3 throughout the terms.

y - 4 = -2/3x + 10/3 Add 4 to both sides of the equation.

y = -2/3x + 22/3

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The domain of this function is {-12,-6,3,15}. Y=-2/3x+7
Evgen [1.6K]

Considering the given function, the table is completed as follows:

x|y

-12|15

-6| 11

3|5

15|-3

<h3>Which is the function?</h3>

The function is defined by:

y = -\frac{2}{3}x + 7

Hence, when x = -12:

y = -\frac{2}{3}(-12) + 7 = 15

When x = -6:

y = -\frac{2}{3}(-6) + 7 = 11

When x = 3:

y = -\frac{2}{3}(3) + 7 = 5

When x = 15:

y = -\frac{2}{3}(15) + 7 = -3

More can be learned about functions at brainly.com/question/25537936

#SPJ1

6 0
2 years ago
Find the measure of angle 1
kaheart [24]

Answer:

112*

Step-by-step explanation:

( 360 - 46 - 90 ) ÷ 2 = 112

8 0
3 years ago
Solve: (a + 11)9 <br><br>plz help ill give the first person brainliest i need it in 10 minutes
ser-zykov [4K]

\\ \tt\longmapsto 9(a+11)

Apply distributive law

  • a(b+c)=ab+ac

\\ \tt\longmapsto 9a+9(11)

\\ \tt\longmapsto 9a+99

8 0
2 years ago
(pls help quick and explain how you got the answers for brainliest)
scoray [572]

You only have to apply the theorem of Pythagoras here. Remember the square on the hypotenuse (the longest side) is equal to the sum of the squares on the other two sides :

1. AB is the hypotenuse, so, according to the theorem we can write :

AB² = AC² + CB²

c² = 5² + 4²

c²= 25 + 16

c² = 41

applying the square root of 41 we get :

c ≈ 6.40 rounded to the hundred

The next cases are exactly the same thing so there is no need for explanation :

2.

AB is the hypotenuse here because it is the biggest side clearl :

AB² = AC² + CB²

25² = 15² + b²

Thus

b² = 25² - 15²

we just subtracted 15² on each side of the equation

b² = 625 - 225

b² = 400

applying the square root of 400 we get

b = √400 = 20

So AC = 20

3. The longest side is clearly AB = 60

So

AB² = AC² + CB²

60² = 40² + a²

subtracting 40² on each side of the equation we get :

a² = 60² - 40²

I let you finish this using your calculator and doing exactly like the previous cases

4.

AB is the hypotenuse,

AB² = AC² + CB²

23² = b² + 14²

Subtracting 14² from each side of the equation we get

b² = 23² - 14²

5.

AB is the biggest side :

AB² = AC² + CB²

29² = 23² + a²

We subtract 23² on each sides of the equation :

a² = 29² - 23²

You can finish with your calculator

6.

AB² = AC² + BC²

78² = b² + 30²

subtraction...

b² = 78² - 30²

Good luck :)

7 0
3 years ago
Suppose m = 2 + 6i, and | m + n | = 3√10, where n is a complex number.
Ksju [112]

Answer: a) √50

b) n = 1 + 7i

Step-by-step explanation:

first, the modulus of a complex number z = a + bi is

IzI = √(a^2 + b^2)  

The fact that n is complex does not mean that n doesn't has a real part, so we must write our numbers as:

m = 2 + 6i

n = a  + bi

Im + nI = 3√10

Im + n I = √(a^2 + b^2 + 2^2 + 6^2)= 3√10

            = √(a^2 + b^2 + 40) = 3√10

             a^2 + b^2 + 40 = 3^2*10 = 9*10 = 90

             a^2 + b^2 = 90 - 40 = 50

            √(a^2 + b^2 ) = InI = √50

The modulus of n must be equal to the square root of 50.

now we can find any values a and b such a^2 + b^2 = 50.

for example, a = 1 and b = 7

1^2 + 7^2 = 1 + 49  = 50

Then a possible value for n is:

n = 1 + 7i

6 0
3 years ago
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