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3 years ago

Write an equation, in slope-intercept form using the given info. (5, 4) m= -2/3

Mathematics

1 answer:

ELEN [110]3 years ago

8 0

Answer:

y = -2/3x + 22/3

Step-by-step explanation:

An equation is written in slope-intercept form when it is written as:

y = mx + b, where m is the slope of the line and b is the y-intercept.

Therefore, because we are given m and a coordinate pair of the line, we can use the point-slope formula to make the equation.

The point-slope formula is $\boxed{y-y_{1}=m(x-x_{1})}$ .

Because we are given only one coordinate pair, it is labeled as $(x_{1}, y_{1})$ .

Now, just plug in this information and solve the equation.

y - 4 = -2/3(x - 5) Distribute the -2/3 throughout the terms.

y - 4 = -2/3x + 10/3 Add 4 to both sides of the equation.

y = -2/3x + 22/3

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Give each rate in miles per hour:

DIA [1.3K]

a) 9/212 = #mph

b)0.000142045 Miles / 0.000277778 hours = # mph

Step-by-step explanation:

a) 9/212 = #mph

1)9 inches divide the length value by 63360 is 0.000142045 Miles

2) 1 hour 3600 seconds in ones hour so 1/3600 =0.000277778

3) take miles/hour

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6 0

3 years ago

Find the slope of the line that passes through (4,-5) and (-2,9)

stiks02 [169]

Answer:

C) -7/3

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(9-(-5))/(-2-4)=(9+5)/-6=14/-6

simplify -14/6 to -7/3

4 0

3 years ago

If a 10 symbol sequence is sent through the channel,what is the probability that up to 3 symbols are in error out of the 10trans

lina2011 [118]

Answer: 0.171887

Step-by-step explanation:

Given that S0 and S1 are binary symbol of equal probabilty;

P(S0) = P(S1) = 0.5

This probability is a Binomial random variable of sequence Sn, where Sn counting the number of success in a repeated trials.

P(Sn =X) = nCx p^x (1-p)^(n-1)

Pr(at most 3) = P(0<= x <=3) = P(X=0) + 0) + P(X=1) + P(X=2) + P(X=3)

Since there are only 2 values that occur in sequence 0 and 1 ( or S0 and S1).Let the distribution be given by the sequence (0111111111),(1011111111),(11011111111),...(1111111110) for Sn= 1 is the sequence for 1 error.

10C0, 10C1, 10C2, and 10C3 is the number of sequences in value for X= 0, 1, 2, 3 having value 0 and others are 1. Let the success be p(S0)=0.5 and p(S1)= 0.5

P(0<= X <=3) = 10C0 × (0.5)^0 × (0.5)^10 + 10C1× (0.5)¹ × (0.5)^9 + 10C2 × (0.5)² × (0.5)^8 + 10C3(0.5)³(0.5)^7

= 1 × (0.5)^10 + 10 × (0.5)^10 + 45 × (0.5)^10 + 120 × (0.5)^10

=0.000977 + 0.00977 + 0.04395 + 0.11719

= 0.171887

3 0

3 years ago

Any help pleaseee?????

attashe74 [19]

Answer: 49

Step-by-step explanation: angle BCA is congruent to angle DCA therefore they are the same measure

3 0

3 years ago