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Llana [10]
3 years ago
14

Find the missing coefficient.

Mathematics
1 answer:
Xelga [282]3 years ago
4 0

Answer:

p = 189

Step-by-step explanation:

p • 3 = 567           reorder the terms 3p = 567        divide both sides by 3

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Jeff and his family are driving to visit his grandmother.they have driven about 30 miles, which is about 2/3 of the way. ow much
finlep [7]
Say you have 3 cakes. How many cakes would you have eaten if you ate 1/3 of the three cakes? One, you have eaten one cake, out of the three you have.

How many cakes do you have left if you eat 2/3 of the three cakes? Two, you have eaten 2 cakes, and have 1 cake left.

It is a similar approach here, except the confusing part is working "forward", when you really have to work "backward". If you have driven 30 miles, and you have driven 2 parts out of the trip when there is 3 parts of the trip, how many miles have you driven? Hint: Dividing 30 by 2 gives you what fraction of the distance to Jeff's grandmother?
6 0
2 years ago
Martha has 3 cards but she wants more.if she makes 5 cards an hour, how many cards will she have after 6 hours?
Genrish500 [490]

Answer:

5x6=30

30+3=33

i think that's the answer

Step-by-step explanation:


8 0
3 years ago
Read 2 more answers
An ice cream cone has a radius of 3 inches and a height of 6 inches. Which measurement is the closest to the volume in cubic inc
zimovet [89]
Just keep in mind that the pie is 3.14
8 0
3 years ago
Let g(x)=Intragal from 0 to x f(t) dt, where r is the function whos graph is shown.
leonid [27]

If

\displaystyle g(x) = \int_0^x f(t) \, dt

then g(x) gives the signed area under f(x) over a given interval starting at 0.

In particular,

\displaystyle g(0) = \int_0^0 f(t) \, dt = 0

since the integral of any function over a single point is zero;

\displaystyle g(4) = \int_0^4 f(t) \, dt = 8

since the area under f(x) over the interval [0, 4] is a right triangle with length and height 4, hence area 1/2 • 4 • 4 = 8;

\displaystyle g(8) = \int_0^8 f(t) \, dt = 0

since the area over [4, 8] is the same as the area over [0, 4], but on the opposite side of the t-axis;

\displaystyle g(12) = \int_0^{12} f(t) \, dt = -8

since the area over [8, 12] is the same as over [4, 8], but doesn't get canceled;

\displaystyle g(16) = \int_0^{16} f(t) \, dt = 0

since the area over [12, 16] is the same as over [0, 4], and all together these four triangle areas cancel to zero;

\displaystyle g(20) = \int_0^{20} f(t) \, dt = 24

since the area over [16, 20] is a trapezoid with "bases" 4 and 8, and "height" 4, hence area (4 + 8)/2 • 4 = 24;

\displaystyle g(24) = \int_0^{24} f(t) \, dt = 64

since the area over [20, 24] is yet another trapezoid, but with bases 8 and 12, and height 4, hence area (8 + 12)/2 • 4 = 40, which we add to the previous area.

5 0
2 years ago
☆15 points☆ select all that apply!​
True [87]

Answer:

c,d

Step-by-step explanation:

because when u solve the problem those both have the same answer

5 0
2 years ago
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