All categories

3 years ago

The median of 32,,21,60,3,5,17

Mathematics

2 answers:

NeX [460]3 years ago

8 0

Answer:

Step-by-step explanation:

Dovator [93]3 years ago

7 0

Answer: 19

Explanation:

Write the number in ascending form:

3,5,17,21,32,60

Find median:

Median = (17+21)/2 = 38/2 = 19

You might be interested in

A new cell phone is on sale for 40% off its original price. The sale price is $48.

anastassius [24]

If it is 40% off, it is selling at 60% of it original price.

The sales price is $48
60% = 58
1% = 58 ÷ 60 = 0.93
100% = 0.93 x 100 = $93

The original price is $93

7 0

2 years ago

Find the slope of the graph below. Help !!

In-s [12.5K]

Answer:

the slope is -1/4

Step-by-step explanation:

the change in y over the change in x from point (-2,-2) to (2,-3) is how to find the slope

y1-y2/x1-x2 = m

-2--3/-2-2 = -1/4

5 0

2 years ago

For which of the following is x = -5 a solution? Select all that apply.

ser-zykov [4K]

Answer:

b. -x^2 + 50 = 25

c. |2x| = 10

d. x < 0

e. 2x < 10

Step-by-step explanation:

x = -5

-(-5)² + 50

-25 + 50 = 25

|2(-5)| = |-10| = 10

-5 < 0

2(-5) = -10 < 10

8 0

2 years ago

The sum of two even numbers is even. the sum of 6 and another number is even. what conjecture can you make about the other numbe

Basile [38]

We can say that the other number is even or it is 0.

6 0

2 years ago

Rewrite with only sin x and cos x.

Annette [7]

Option A

$\cos 3 x=\cos x-4 \cos x \sin ^{2} x$

Solution:

Given that we have to rewrite with only sin x and cos x

Given is cos 3x

$cos 3x = cos(x + 2x)$

We know that,

$\cos (a+b)=\cos a \cos b-\sin a \sin b$

Therefore,

$\cos (x+2 x)=\cos x \cos 2 x-\sin x \sin 2 x$ ---- eqn 1

We know that,

$\sin 2 x=2 \sin x \cos x$

$\cos 2 x=\cos ^{2} x-\sin ^{2} x$

Substituting these values in eqn 1

$\cos (x+2 x)=\cos x\left(\cos ^{2} x-\sin ^{2} x\right)-\sin x(2 \sin x \cos x)$ -------- eqn 2

We know that,

$\cos ^{2} x-\sin ^{2} x=1-2 \sin ^{2} x$

Applying this in above eqn 2, we get

$\cos (x+2 x)=\cos x\left(1-2 \sin ^{2} x\right)-\sin x(2 \sin x \cos x)$

$\begin{aligned}&\cos (x+2 x)=\cos x-2 \sin ^{2} x \cos x-2 \sin ^{2} x \cos x\\\\&\cos (x+2 x)=\cos x-4 \sin ^{2} x \cos x\end{aligned}$

$\cos (x+2 x)=\cos x-4 \cos x \sin ^{2} x$

Therefore,

$\cos 3 x=\cos x-4 \cos x \sin ^{2} x$

Option A is correct

7 0

2 years ago