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3 years ago

12

What is the difference of the two polynomials?

2 answers:

enyata [817]3 years ago

5 0

Answer:

B) 7y² + 8xy - 3 .

Step-by-step explanation:

Given : (7y² + 6xy) – (–2xy + 3).

To find : What is the difference of the two polynomials.

Solution : We have given

(7y² + 6xy) – (–2xy + 3).

Removing the pantheists

(7y² + 6xy) + 2xy - 3).

Combine like terms

7y² + 8xy - 3 .

Therefore, B) 7y² + 8xy - 3 .

Alex787 [66]3 years ago

3 0

The answer to that question is B.

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According to government data, 75% of employed women have never been married. Rounding to 4 decimal places, if 15 employed women

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We are given that According to government data, 75% of employed women have never been married.

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b. That at most 2 of them have never been married?

At most two means at x = 0 ,1 , 2

So, $P(X=r) =^{15}C_0 (0.75)^0 (0.25^{15-0}+^{15}C_1 (0.75)^1 (0.25^{15-1}+^{15}C_2 (0.75)^2 (0.25^{15-2}$

$P(X=r) =(0.75)^0 (0.25^{15-0}+15 (0.75)^1 (0.25^{15-1}+\frac{15!}{2!(15-2)!} (0.75)^2 (0.25^{15-2})$

$P(X=r) =9.9439 \times 10^{-6}$

c. That at least 13 of them have been married?

P(x=13)+P(x=14)+P(x=15)

$={15}C_{13}(0.75)^{13} (0.25^{15-13})+{15}C_{14} (0.75)^{14}(0.25^{15-14}+{15}C_{15} (0.75)^{15} (0.25^{15-15})$

$=\frac{15!}{13!(15-13)!}(0.75)^{13} (0.25^{15-13})+\frac{15!}{14!(15-14)!} (0.75)^{14}(0.25^{15-14}+{15}C_{15} (0.75)^{15} (0.25^{15-15})$

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