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vladimir1956 [14]
3 years ago
11

Find the slope of the line that passes through the points (-8, 11 ) and ( 24, -9).

Mathematics
1 answer:
Ray Of Light [21]3 years ago
5 0

Answer:

- 5/8

Step-by-step explanation:

-9-11/24-(-8)= -20/32 = - 5/8

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The last answer is the correct one.

If it does not make sense ask for clarification.

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I’m pretty confused on this question. Anyone know the answers?
Afina-wow [57]

Answer:

see explanation

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y-intercept )

• If m > 0, then the line slopes upwards from left to right ( increases )

• If m < 0, then the line slopes downwards from left to right ( decreases )

(a)

y + x = 3 ( subtract x from both sides )

y = - x + 3 ← in slope-intercept form

with m = - 1 ⇒ decreasing from left to right

(c)

y = 4x + 8 ← is in slope-intercept form

with m = 4 ⇒ increasing from left to right

the equation of a line in the form x = c represents a vertical line, where c is the value of the x-coordinates the line passes through

(b)

x - 5 = 0 ( add 5 to both sides )

x = 5 ← is a vertical line

the equation of a line in the form y = c represents a horizontal line, where c is the value of the y-coordinates the line passes through

(d)

\frac{y}{4} = - 6 ( multiply both sides by 4 )

y = - 24 ← is a horizontal line


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3 years ago
If b equals 16.3 and a equals 21.7 what is angle A
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Step-by-step explanation:

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Read 2 more answers
Does anyone know how to solve this? It’s really starting to stress me out.
bekas [8.4K]

Answer:

π − 12

Step-by-step explanation:

lim(x→2) (sin(πx) + 8 − x³) / (x − 2)

If we substitute x = u + 2:

lim(u→0) (sin(π(u + 2)) + 8 − (u + 2)³) / ((u + 2) − 2)

lim(u→0) (sin(πu + 2π) + 8 − (u + 2)³) / u

Distribute the cube:

lim(u→0) (sin(πu + 2π) + 8 − (u³ + 6u² + 12u + 8)) / u

lim(u→0) (sin(πu + 2π) + 8 − u³ − 6u² − 12u − 8) / u

lim(u→0) (sin(πu + 2π) − u³ − 6u² − 12u) / u

Using angle sum formula:

lim(u→0) (sin(πu) cos(2π) + sin(2π) cos(πu) − u³ − 6u² − 12u) / u

lim(u→0) (sin(πu) − u³ − 6u² − 12u) / u

Divide:

lim(u→0) [ (sin(πu) / u) − u² − 6u − 12 ]

lim(u→0) (sin(πu) / u) + lim(u→0) (-u² − 6u − 12)

lim(u→0) (sin(πu) / u) − 12

Multiply and divide by π.

lim(u→0) (π sin(πu) / (πu)) − 12

π lim(u→0) (sin(πu) / (πu)) − 12

Use special identity, lim(x→0) ((sin x) / x ) = 1.

π (1) − 12

π − 12

3 0
3 years ago
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