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yKpoI14uk [10]
3 years ago
15

Directions - For the graph, identify the key components and create a system of inequalities.

Mathematics
1 answer:
Marizza181 [45]3 years ago
6 0

Answer:

I will give you the inequalities.

Inequality ofr blue line is: y= -1/3x+1

Inequality for red line is y= 1/2x+2

Step-by-step explanation:

M is the slope and B is the y-intercept I hope that can help you to find M and B. If you can't figure it out coment and I will be hapoy to help you further!

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What is the value of the equation 9/2÷(-3)0
Finger [1]
The answer just keeps coming back to zero dude it's simple you can't really calculate this either way the value of it would just be zero you can't simplify it or anything
6 0
3 years ago
A line with a slope of -4 passes through the point (0, 0). What is its equation in
Dahasolnce [82]

Answer: y = -4x

Step-by-step explanation: You would use the formula y = mx + b to solve your problem. When you plug the numbers in, you get y = -4x. There would be no "+ b" because in this case, the y-intercept (b) is equal to zero. Therefore, you would not need to write "y = -4x + 0" because that would not be the equation in its simplest form.

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Can someone help me with this question?
Anon25 [30]
1/10 x 90  I think that's the answer



4 0
3 years ago
Read 2 more answers
The sector COB is cut from the circle with center O. The ratio of the area of the sector removed from the whole circle to the ar
mafiozo [28]

Answer:

Ratio = \frac{R^2 - r^2 }{ r^2}

Step-by-step explanation:

Given

See attachment for circles

Required

Ratio of the outer sector to inner sector

The area of a sector is:

Area = \frac{\theta}{360}\pi r^2

For the inner circle

r \to radius

The sector of the inner circle has the following area

A_1 = \frac{\theta}{360}\pi r^2

For the whole circle

R \to Radius

The sector of the outer sector has the following area

A_2 = \frac{\theta}{360}\pi (R^2 - r^2)

So, the ratio of the outer sector to the inner sector is:

Ratio = A_2 : A_1

Ratio = \frac{\theta}{360}\pi (R^2 - r^2) : \frac{\theta}{360}\pi r^2

Cancel out common factor

Ratio = R^2 - r^2 : r^2

Express as fraction

Ratio = \frac{R^2 - r^2 }{ r^2}

6 0
3 years ago
A cross-country team had a total of 10 practices last week, with each practice being in the morning or the afternoon. During eac
GalinKa [24]

x= morning

y = afternoon

 x + y = 10

x=10-y

5x + 6y =57

5(10-y) +6y =57

50-5y +6y =57

y=7

x=10-7 =3

 check 3*5 = 15, 7*6 = 42, 42 + 15 = 57


3 morning practices

3 0
3 years ago
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