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2 years ago

Was a major accomplishment of both Tutankhamun and Rameses II. Plz help

Mathematics

1 answer:

LenKa [72]2 years ago

6 0

Answer:

AA similarity. The angles in both are the same.

Edit: I don't know if you need this, but a major accomplishment of King Tut and Ramses was that they encouraged the following of ancient religious beliefs among the Egyptian people .

Hope that this helps!

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Complete. Express the product in simplest form. 2/5 of 7/10 =

tester [92]

Of means multiply in math (most of the time).
So multiply.
2/5 x 7/10 = 14/50 divided by 2/2 = 7/25

3 0

3 years ago

Read 2 more answers

X + 2 > -8 a. x > -6 b. x > -10 c. x <-10 d. x < -6

PSYCHO15rus [73]

The answer is: [B]: x > -10
__________________________
Explanation:
___________
Given the inequality:
___________
→ x + 2 > - 8 ;
____________
→ Subtract "2" from EACH side; to isolate "x" on one side; and solve, or simplify, for "x" ;
_______________________
→ x + 2 − 2 > - 8 − 2 ; to get:
_______________________
→ x > -10 ; which is: 'Answer choice: [B]'.
_______________________

6 0

2 years ago

What is the length of the strip of seaweed around the outside of the sushi?

SashulF [63]

To find the circumference of a round object, you will take the diameter and multiply is by pi to get 78.5mm

8 0

2 years ago

On the first day after the new moon, 2% of the Moon's surface is illuminated. On the second day, 6% is illuminated. Based on thi

maxonik [38]

Answer:

50%: day 13

100%: day 26

Step-by-step explanation:

We are given two days and the amount of the moon that is illuminated. The two days are points on a straight line.

(1, 0.02), (2, 0.06)

y = mx + b

m = (0.06 - 0.02)/(2 - 1) = 0.04

y = 0.04x + b

0.02 = 0.04(1) + b

b = -0.02

y = 0.04x - 0.02

We want y = 50% = 0.5

0.04x - 0.02 = 0.5

0.04x = 0.52

x = 13

y = 100% = 1

0.04x - 0.02 = 1

0.04x = 1.02

x = 25.5

7 0

2 years ago

Read 2 more answers

Binomial Probability

ASHA 777 [7]

Answer:

4.39% theoretical probability of this happening

Step-by-step explanation:

For each coin, there are only two possible outcomes. Either it lands on heads, or it lands on tails. The probability of a coin landing on heads is independent of other coins. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$