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bezimeni [28]
3 years ago
13

A soccer league has 170 players. Of those players 60% are boys. How many boys are in the soccer league?​

Mathematics
2 answers:
sweet-ann [11.9K]3 years ago
8 0

Answer:

102

Step-by-step explanation:

60% of 170= 102

Kay [80]3 years ago
7 0

Answer:

102

Step-by-step explanation:

170*(60%) = 170 *0.6= 102

60% of the entire part is also 0.6

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How to find inflection points from first derivative
Mekhanik [1.2K]

Answer:

For finding the inflection points you'll have to put the first derivative equal to zero and solve for x. After you've done that, you can plug in the x you've just found into the original function and find also the y, so you'll find the ordered pair (x,y) of the inflection point(s).

7 0
2 years ago
What is the distance between the points (-6,7) and (-1,1)?
Nataly_w [17]

Answer:

\sqrt{61}

Step-by-step explanation:

To find the distance, we first do B - A, where B is (-6, 7) and A is (-1, 1):

(-6, 7) - (-1, 1) = (-6+1, 7-1) = (-5, 6)

Imagine it as a triangle, where the hypotenuse is the distance, and -5 and 6 are the lengths of the sides.  

To find the hypotenuse (Pythagorean Theorem):  \sqrt{(-5)^2+6^2} =\sqrt{25+36} =\sqrt{61}

The answer is the square root of 61.

4 0
2 years ago
Read 2 more answers
2.
Tcecarenko [31]

Answer:

ggggggggggggggggggggggggggggggg

Step-by-step explanation:

ggggggggggggggggggggggggggggggg

4 0
2 years ago
Answer quick for brainliest
Verizon [17]

Answer:

y=-2x+4

Step-by-step explanation:

Hello there!

Using y=mx+b, -2 is the slope and 4 is the y-intercept.

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7 0
3 years ago
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It is important that face masks used by firefighters be able to withstand high temperatures because firefighters commonly work i
USPshnik [31]

Answer:

The 93% confidence interval for the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574). This means that we are 93% sure that the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 55, \pi = \frac{24}{55} = 0.4364

93% confidence level

So \alpha = 0.07, z is the value of Z that has a pvalue of 1 - \frac{0.07}{2} = 0.965, so Z = 1.81.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4364 - 1.81\sqrt{\frac{0.4364*0.5636}{55}} = 0.3154

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4364 + 1.81\sqrt{\frac{0.4364*0.5636}{55}} = 0.5574

The 93% confidence interval for the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574). This means that we are 93% sure that the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574).

8 0
3 years ago
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