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yawa3891 [41]
3 years ago
9

Find x. 4 square root 3 2 square root 3 8 8 square root 3

Mathematics
1 answer:
UkoKoshka [18]3 years ago
6 0

Answer:

8

Step-by-step explanation:

sin \:  \alpha  =  \frac{opp}{hyp}  \\ sin \: 30 =  \frac{4}{x}  \\  \frac{1}{2}  =  \frac{4}{x}  \\

x = 4 \times 2 \\ x = 8

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ethan earned 5% of the maximum number of points possible . It ethan earned 40 points , what is the maximum number of points poss
Morgarella [4.7K]

Answer:

3840

Step-by-step explanation:

4 0
3 years ago
Rewrite in mathematical language. Every negative integer J is less than or equal to its inverse.
Luda [366]

Answer:

-J \leq J

Step-by-step explanation:

Given

Negative integer J

Required

Represent as an inequality of its inverse

The question didn't state if it's additive inverse or multiplicative inverse;

<em>Since the question has to do with negation, I'll assume it's an additive inverse</em>

<em></em>

The inverse of -J is +J

To represent as an inequality (less than or equal), we have:

-J \leq +J

Solving further, it gives

-J \leq J

3 0
3 years ago
Which function is undefined for x = 0? y=3√x-2 y=√x-2 y=3√x+2 y=√x=2
Mkey [24]

For this case, we have to:

By definition, we know:

The domain of f (x) = \sqrt [3] {x} is given by all real numbers.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. In the same way, its domain will be given by the real numbers, independently of the sign of the term inside the root. Thus, it will always be defined.

So, we have:

y = \sqrt [3] {x-2} withx = 0: y = \sqrt [3] {- 2} is defined.

y = \sqrt [3] {x+2}with x = 0:\ y = \sqrt [3] {2} is also defined.

f (x) = \sqrt {x}has a domain from 0 to ∞.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. For it to be defined, the term within the root must be positive.

Thus, we observe that:

y = \sqrt {x-2} is not defined, the term inside the root is negative whenx = 0.

While y = \sqrt {x+2} if it is defined for x = 0.

Answer:

y = \sqrt {x-2}

Option b

6 0
3 years ago
PLEASE HELP ME !! PLEASE !!
Yakvenalex [24]
I think that it is a ok
6 0
3 years ago
What is the difference between 12/8 and 3/4?
Katen [24]

Answer:

3/4

Step-by-step explanation:

Difference means subtraction

12/8 - 3/4

We need a common denominator of 8

12/8 - 3/4 * 2/2

12/8  - 6/8

 6/8

Divide by 2 in the numerator and denominator

 3/4

6 0
3 years ago
Read 2 more answers
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