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3 years ago

8

A rectangular box is 8 inches long, 10 inches wide and 6 inches tall. What is the approximate length of its longest diagonal? 10

inches 14.1 inches 4.9 inches 24 inches

1 answer:

andreyandreev [35.5K]3 years ago

5 0

Answer:

d = 10 inches

Step-by-step explanation:

It is given that,

The length, breadth and the height of a rectangular box is 8 inches×10 inches ×6 inches

We need to find the length of its longest diagonal.

In a rectangle, 6 inches will act as perpendicular and 8 inches will be base. The diagonal can be calculated using Pythagoras theorem as follows :

$d=\sqrt{8^2+6^2} \\\\=\sqrt{64+36}\\\\=10\ \text{inches}$

So, the length of its diagonal is 10 inches.

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The surface area of a square pyramid is 136 square inches. The base is 4 inches. What is the slant area

zheka24 [161]

34 inches. How you work it out would be base x height. This means to work out the height, you divide the total area by the base. 136/4 is 34

4 0

3 years ago

Help!!!!!!!!!!!!!!!!!!!!!!!<br><br><br> please ty<br><br> c:

Aleksandr [31]

Use the formula for the area of a triangle, and fill in the given information.
.. A = (1/2)*b*h
.. 36 in^2 = (1/2)*b*(9 in)
.. (72 in^2)/(9 in) = b . . . . . . . . multiply by 2, divide by 9 in
.. 8 in = b

The base is "none of the above", 8 inches.

_____
This question has a couple of problems:
.. 1) area is not measured in "inches"; it is measured in "square inches."
.. 2) ALL of the offered answer choices are INCORRECT.

4 0

3 years ago

Find the solutions to x⁴-5x²-36=0 and the x-intercepts of the graph of y=x⁴-5x²-36.

disa [49]

Answer:

The solutions $x^4-5x^2-36=0$ are $x=3,\:x=-3,\:x=2i,\:x=-2i$ and the x-intercepts of $y=x^4-5x^2-36$ are $x=3,\:x=-3$

Step-by-step explanation:

Finding the solutions to $x^4-5x^2-36$ means finding the roots, a root is where the function is equal to zero.

The x-intercept is the point at which the graph crosses the x-axis. At this point, the y-coordinate is zero.

To find the roots you need to:

Rewrite the equation with $u=x^2$ and $u^2=x^4$

$u^2-5u-36=0$

Solve by factoring

$\mathrm{Break\:the\:expression\:into\:groups}\\u^2-5u-36=\left(u^2+4u\right)+\left(-9u-36\right)$

$\mathrm{Factor\:out\:}u\mathrm{\:from\:}u^2+4u=u\left(u+4\right)$

$\mathrm{Factor\:out\:}-9\mathrm{\:from\:}-9u-36=-9\left(u+4\right)$

$u^2-5u-36=u\left(u+4\right)-9\left(u+4\right)$

$\mathrm{Factor\:out\:common\:term\:}u+4\\\left(u+4\right)\left(u-9\right)$

$u^2-5u-36=\left(u+4\right)\left(u-9\right)=0$

Using the Zero factor Theorem: if ab = 0 then a = 0 or b = 0 (or both a = 0 and b = 0)

The solutions to the quadratic equation are:

$\:u=-4,\:u=9$

Substitute back $u=x^2$ , solve for x

$x^4-5x^2-36=(u-9)(u+4)=(x^2-9)(x^2+4)$

Apply the difference of squares formula

$x^4-5x^2-36=(x^2-9)(x^2+4)=(x-3)(x+3)(x^2+4)$

$(x-3)(x+3)(x^2+4)=0$

Using the Zero factor Theorem: if ab = 0 then a = 0 or b = 0 (or both a = 0 and b = 0)

The solutions are:

$\:x=3,\:x=-3,\:x=2i,\:x=-2i$

Because two of the solutions are complex roots the only x-intercepts are $x=3,\:x=-3$

3 0

3 years ago

418,832 rounded to nearest ten thousand

nika2105 [10]

Answer: 419,000

Step-by-step explanation:

418,832

In the thousand's place is an 8. Next to it is an 8.

If the # is biiger than 5 it moves up. if it's 4 or less lower it.

the answer is 419,000

7 0

3 years ago

Read 2 more answers

If 7/35 = 4/y, what is y?

Fittoniya [83]

Answer:

<h2>y = 20</h2>

Step-by-step explanation:

$\frac{7}{35} = \frac{4}{y}$

<u>First of all cross multiply</u>

That's

7y = 140

<u>Divide both sides by 7</u>

That's

$\frac{7y}{7} = \frac{140}{7}$

We have the final answer as

<h3>y = 20</h3>

Hope this helps you

8 0

3 years ago