The molecular formula of a compound is C₂H₂O₄.
Take 100 grams of compound:
1) ω(C) = 26.7% ÷ 100% = 0.267
m(C) = ω(C) × m(compound)
m(C) = 0.267 × 100 g.
m(C) = 26.7 g.
n(C) = m(C) ÷ M(C).
n(C) = 26.7 g ÷ 12 g/mol.
n(C) = 2.22 mol; amount of carbon
2) ω(H) = 2.2 % ÷ 100% = 0.022
m(H) = 0.022 × 100 g.
m(H) = 2.2 g.
n(H) = 2.2 g ÷ 1 g/mol.
n(H) = 2.2 mol; amount of hydrogen
3) ω(O) = 71.1 % ÷ 100%.
ω(O) = 0.711
m(O) = 0.711 × 100 g
m(O) = 71.1 g
n(O) = 71.1 g ÷ 16 g/mol
n(O) = 4.4 mol; amount of oxygen
4) n(C) : n(H) : n(O) = 2.2 mol : 2.2 mol : 4.4 mol /2.2 mol.
n(C) : n(H) : n(O) = 1 : 1 : 2
M(CHO₂) = 45 amu; empirical formula
90 amu ÷ 45 amu = 2 CHO₂
More info about empirical formula: brainly.com/question/1873039
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Answer:</h3>
1026.05 kJ
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Explanation:</h3>
- The Quantity of heat is calculated by multiplying the mass of a substance by specific heat capacity and the change in temperature.
- However, condensation takes place at a constant temperature.
- Therefore, Quantity of heat is calculated by multiplying mass by the latent heat of vaporization.
In this case we are given;
Mass of steam as 454 g
To calculate the amount of heat released we must know the value of latent heat of vaporization;
The latent heat of vaporization of steam is 2260 J/g
Therefore;
Heat released, Q = 454 g × 2260 J/g
=1026040 Joules
But, 1000 joules = 1 kilo-joules
Thus, Q = 1026.04 kJ
Hence, the amount of heat released is 1026.05 kJ
If I understand you correctly, then this is the equation for the breakdown of monosaccharide.
monosaccharide --> Carbon dioxide + water
Answer:
We are asked to describe the half-life of the radioactive materials.
- Hence the 3rd option is correct
