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STatiana [176]
2 years ago
14

How many atoms are there in 2.43 g of calcium?

Chemistry
1 answer:
Evgen [1.6K]2 years ago
3 0

Answer:

Explanation:

We're asked to calculate the number of atoms of

Ca

in

153

g Ca

.

What we must first do is convert the given mass of calcium to moles of calcium, using its molar mass (referring to a periodic table, this is

40.08

g

mol

):

153

g Ca

(

1

mol Ca

40.08

g Ca

)

=

3.82

mol Ca

Using Avogadro's number,

6.022

×

10

23

particles

mol

, we can calculate the number of atoms present:

3.82

mol Ca

(

6.022

×

10

23

atoms Ca

1

mol Ca

)

=

2.30

×

10

24

atoms Ca

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The Lewis structures are in image attached.

Explanation:

Lewis symbol is a representation of an element symbol along with its valence electrons around it in the form of dot(s).

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Magnesium's atomic number is 12 in which only 2 electrons are present in its valence shell .So, in order to gain noble gas stability it will loose 2 electrons to completes its octet.

In the Lewis symbol no dot shown as magnesium has lost its 2 electrons.

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Calcium's atomic number is 20 in which only 2 electrons are present in its valence shell .So, in order to gain noble gas stability it will loose 2 electron to completes its octet.

In the Lewis symbol no dot shown as calcium has lost its 2 electron.

Ca= 1s^22s^22p^63s^23p^64s^2

Ca^{2+}=1s^22s^23p^6^23p^64s^0

(e) K

Potassium's atomic number is 19 in which only 1 electrons are present in its valence shell .So, in order to gain noble gas stability it will loose 1 electron to completes its octet.

In the Lewis symbol no dot shown as calcium has lost its 1 electron.

K= 1s^22s^22p^63s^23p^64s^1

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(f) Br

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Br=1s^22s^22p^63s^23p^63d^{10}4s^24p^5

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(g) Sr

Strontium's atomic number is 38 in which only 2 electrons are present in its valence shell .So, in order to gain noble gas stability it will loose 2 electron to completes its octet.

In the Lewis symbol no dot shown as calcium has lost its 2 electron.

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