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erica [24]
3 years ago
5

Pls help me guys! Thanks =P

Mathematics
2 answers:
tigry1 [53]3 years ago
6 0
The  answer of t he  trapezoid  area  problem is  112.
tankabanditka [31]3 years ago
4 0
The answer would be, B-112in2
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What is the gradient of the graph shown ? Give your answer in its simplest form
Sedbober [7]

Answer:

-2

Step-by-step explanation:

choose any point on the graph

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The Latin Club charted a bus to travel to and participate in a state competition. The cost for each adult to ride the bus was $2
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<span>a+s =17 25a + 15s = 305</span>
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3 years ago
What is 9/12a = 1 ? Also what is 6/5b = 1 ? And Finaly what is 12c = 1 ?
ivolga24 [154]

Step-by-step explanation:

hope I understand your question

a = 9/12

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4 0
3 years ago
Please hurry and tell me the answer.
vaieri [72.5K]

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Step-by-step explanation:

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bogdanovich [222]
Problem 1)

AC is only perpendicular to EF if angle ADE is 90 degrees

(angle ADE) + (angle DAE) + (angle AED) = 180
(angle ADE) + (44) + (48) = 180
(angle ADE) + 92 = 180
(angle ADE) + 92 - 92 = 180 - 92
angle ADE  = 88

Since angle ADE is actually 88 degrees, we do NOT have a right angle so we do NOT have a right triangle

Triangle AED is acute (all 3 angles are less than 90 degrees)

So because angle ADE is NOT 90 degrees, this means AC is NOT perpendicular to EF

-------------------------------------------------------------

Problem 2)

a) The center is (2,-3) 

The center is (h,k) and we can see that h = 2 and k = -3. It might help to write (x-2)^2+(y+3)^2 = 9 into (x-2)^2+(y-(-3))^2 = 3^3 then compare it to (x-h)^2 + (y-k)^2 = r^2

---------------------

b) The radius is 3 and the diameter is 6

From part a), we have (x-2)^2+(y-(-3))^2 = 3^3 matching (x-h)^2 + (y-k)^2 = r^2

where
h = 2
k = -3
r = 3

so, radius = r = 3
diameter = d = 2*r = 2*3 = 6

---------------------

c) The graph is shown in the image attachment. It is a circle with center point C = (2,-3) and radius r = 3.

Some points on the circle are

A = (2, 0)
B = (5, -3)
D = (2, -6)
E = (-1, -3)

Note how the distance from the center C to some point on the circle, say point B, is 3 units. In other words segment BC = 3.

6 0
3 years ago
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