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4 years ago

Pls help me guys! Thanks =P

Mathematics

2 answers:

tigry1 [53]4 years ago

6 0

The answer of t he trapezoid area problem is 112.

tankabanditka [31]4 years ago

4 0

The answer would be, B-112in2

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An exponentially function is expressed in the form y = axb^x . The relation represents a growth when _ and a decay when _ .

Sergio [31]

Answer:

The relation represents a growth when b>1 and a decay when 0<b<1

Step-by-step explanation:

Any function in the form $f(x)= a(b^x)$ , where a > 0, b > 0 and b not equal to 1 is called an exponential function with base b. If 0 < b < 1. It is an example of an exponential decay. The general shape of an exponential with b > 1 is an example of exponential growth. An exponential function is expressed in the form $y=a(b^x)$ The relation represents a growth when b >1 and a decay when 0<b<1.

3 0

3 years ago

Joe paid 14.00 for a board game this is 70% off the original price what is the original price?

soldi70 [24.7K]

Answer:

The correct option is B.

Step-by-step explanation:

It is given that Joe paid 14.00 for a board game this is 70% of the original price what is the original price.

Let the original price of board game be x.

$x\times \frac{70}{100}=14$

$x\times \frac{7}{10}=14$

Multiply both sides by 10.

$7x=140$

Divide both sides by 7.

$x=20$

The original price is 20. Therefore the correct option is B.

6 0

4 years ago

Karl bought 3 1/2 gallons of milk that cost $2.70 per gallon. What was the total cost of the milk? Enter your answer in the

pav-90 [236]

Answer:

9.45

Step-by-step explanation:

2.70*3 = 8.10

8.10 + 1.35= 9.45

7 0

3 years ago

Read 2 more answers

Suppose that X has an exponential distribution with mean equal to 10. Determine the following: a. P(X > 10) b. P(X > 20) c

GrogVix [38]

Answer:

(a) The value of P (X > 10) is 0.3679.

(b) The value of P (X > 20) is 0.1353.

(d) The value of x is 30.

Step-by-step explanation:

The probability density function of an exponential distribution is:

$f(x)=\lambda e^{-\lambda x};\ x>0, \lambda>0$

The value of E (X) is 10.

The parameter λ is:

$\lambda=\frac{1}{E(X)}=\frac{1}{10}=0.10$

(a)

Compute the value of P (X > 10) as follows:

$P(X>10)=\int\limits^{\infty}_{10} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{10} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{10}\\=|e^{-0.10 x} |^{\infty}_{10}\\=e^{-0.10\times10}\\=0.3679$

Thus, the value of P (X > 10) is 0.3679.

(b)

Compute the value of P (X > 20) as follows:

$P(X>20)=\int\limits^{\infty}_{20} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{20} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{20}\\=|e^{-0.10 x} |^{\infty}_{20}\\=e^{-0.10\times20}\\=0.1353$