Question

A ball is thrown straight down with a velocity of 12 m/s; what will be its velocity 2.0 s after being released?

Answer 1

Answer:

$v = 31.6m/s$

Explanation:

Given

$Initial\ Velocity, u = 12m/s$

$Time, t = 2.0s$

Required

Determine the final velocity, v

Using the first equation of motion

$v = u + at$

But in this case;

a = g = acceleration of gravity

So:

$v = u + gt$

Substitute values for u and t

$v = 12 + g * 2$

$v = 12 + 2g$

Take g as 9.8m/s²

$v = 12 + 2 * 9.8$

$v = 12 + 19.6$

$v = 31.6m/s$

Hence, the velocity is 31.6m/s