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3 years ago

what does the density of an object tell you about the molecular arrangement of the atoms in an object

Physics

1 answer:

Andrews [41]3 years ago

4 0

Answer:

If the density of the object is high its molecular arrangement is compact while if the density is lows its molecular arrangement isnt that compact

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100 POINTS 100 POINTS 100 POINTS!!!!!<br> HELP PLEASE I DON'T KNOW WHAT TO DO!!!!!

Westkost [7]

Answer:

block 2 or 4

because of the distribution of weight and force being applied to the object

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3 years ago

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Alondra applies 24 N of force to the end of a stick (a type of lever) to open a can of paint.

Assoli18 [71]

Answer:

1/4

Explanation:

Mechanical Advantage = Load/Effort

Given

Effort applied = 24N

Load = 6N

Substitute

MA = 6/24

MA = 1/4

Hence the mechanical advantage is 1/4

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3 years ago

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Which receptors are responsible for the production of saliva (A) auditory receptors (B) optic receptors (C) skin receptors (D) t

Fudgin [204]

Answer:

$\large \boxed{\sf D. \ taste \ receptors}$

Explanation:

When activated, the receptor most likely prompting the production of saliva is the taste receptor. When food enters the mouth, the salivary glands produce the saliva upon the sensation of taste.

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3 years ago

What happens to the electronegativity of elements as you move from bottom left to upper right across the periodic table?

Paraphin [41]

It increases. As it moves it <span>increases while the movement is in process.

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3 0

3 years ago

A revolutionary war cannon, with a mass of 2260 kg, fires a 15.5 kg ball horizontally. The cannonball has a speed of 109 m/s aft

Anton [14]

Answer:

The gain in velocity is 0.37m/s

Explanation:

We need solve this problem though the conservation of momentum. That is,

$m_1 v_1 = m_2 v_2$

$m_1=2260Kg\\m_2=15.5Kg\\v_2= 109m/s$

Using the equation to find $v_1$ ,

$v_1=\frac{m_2 v_2}{m_1}\\v_1=\frac{15.5*109}{2260}\\v_1= 0.7475$

Using the conservation of energy equation, we have,

$KE= \frac{1}{2}m*v^2$

$KE_{cball}=\frac{1}{2}(15.5)(109)^2=92077.75J$

$KE_{cannon}=\frac{1}{2}(2260)(0.7475)^2=631.39J$

$Total KE= 92077.75+13425530=92708.9J$

Now this energy over the cannonball

$KE=\frac{1}{2}m*v_2^2$

$92708.9=\frac{1}{2}15.5v_2^2$

$V_2 = 109.37m/s$

The gain in velocity is 0.37m/s

4 0

3 years ago