Answer:
ω = 3.61 rad/sec
Explanation:
Firstly, we should know that the bug will not slip if friction can provide sufficient opposing force.
μmg = mv^2/r = mω^2r
Thus;
μg = ω^2r
ω^2 = μg/r
ω = √(μg/r)
ω = √(0.321 * 9.8)/0.241
ω = √(13.05)
= 3.61 rad/sec
Answer:0.1759 v
Explanation:
Intensity of wave at receiver end is
I=
I=
I=
Amplitude of electric field at receiver end

Amplitude of induced emf
=
=
=
the axis acts against and it would be a contact force
I think F= mv²/r
And F=ma
So, ma = mv²/r
a = v²/r
a = 100/5
a = 20 m/s
- The data for the first part of the experiment support the first hypothesis.
- As the force applied to the cart increased, the acceleration of the cart increased.
- Since the increase in the applied force caused the increase in the cart's acceleration, force and acceleration are directly proportional to each other, which is in accordance with Newton's second law.
When we state something about the results on the basis whether the observed data supports the original hypothesis, we say that we are concluding the results.
What is the relationship between force and acceleration based on Newton's 2nd law?
Newton's second law of motion can be formally stated as follows: The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.
Learn more about Newton's second law of motion brainly.com/question/13447525
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