Well, we can denote L and W for the length and width respectively. Lets say the A is the area, we have: 1. A=(L × W) as well as 2. 2(L+W)=400. We rearrange the second equation to get 3. W=200-L. From this, we can see that 0<L<200. Substitute the third equation into the first to get A=(200L-L²). put this formula into the scientific calculator and you will find a parabola with a maximum. That would be the maximum area of the enclosed area. Alternatively, we can say that L is between 0 and 200 when the area equals 0. (The graph you find will be area against length). As the maximum is generally found halfway, we substitute 100 into the equation and we end up with 10000.
Hope this helps.
<span>Straight (it's a straight line!), full rotation (a circle), but nothing else since you can't measure the exact angle of it</span>
I will create a set of arbitrary constants (x1,y1) (x2,y2)
slope = y2-y1/x2-x1
y = (y2-y1/x2-x1)x + b
y2 = (y2-y1/x2-x1)x2 + b
b = y2 - (y2-y1/x2-x1)x2
y = (y2-y1/x2-x1)x + [y2 - (y2-y1/x2-x1)]
Choose any points and just
Plug the values and you have a linear function.
NOT SURE IF THAT'S WHAT THE QUESTION WANTS.
The dice only has 6 sides so if you need to roll a 2 or less that only leaves the number one. So it would be 2/6
Answer:
At the bottom!
Step-by-step explanation:
Put the two equations into the same standard form:
2x-y=8
-5x+2y=3
Now if you add the two equations up, guess what will happen?
You will "eliminate" the y variable, and only be left with the x variable.
Technically, you will get:
2x-y+2+28-5x+29+2y=8+23
-3x+20y=11
-3x=11
