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yaroslaw [1]
3 years ago
9

Can someone please help me with this?

Mathematics
1 answer:
Verdich [7]3 years ago
5 0
The way this problem is stated is that you put 1 grain of rice on the first square, the second square has 2 grains of rice. The third square has 4 grains of rice and you keep on doubling from there. When you tell me there is a 0 square, I'm not sure what you mean.
That would mean (to me) that square 1 has 2 grains of rice
Square 2 has 4 grains of rice
Square 3 has 8 grains of rice
The table goes up to 64 squares on a chess board.
2^64 which is (rounded) to about 1.84 with 17 zeros behind the 1.84.
My calculator says the answer is 1.84 * 10^19
I think you want 
2^64<<<<<answer.
Or maybe
y =R(x) =  2^x <<<< answer.
where the domain is 0 <=x <= 64 contained in the integers.

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Which expression finds the length of side b of this right triangle. PLEASE HELP. I’LL GIVE BRAINIEST
Monica [59]

Answer:

The answer is b = √(c² - a²).

Step-by-step explanation:

For right angle triangle, you can apply Pythagoras Theorem where c² = a² + b² .

3 0
3 years ago
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the perimeter of rectangle is 44 inches.if the length of the rectangle is 7 more than half its width.what is the area of the rec
pentagon [3]

Answer:

120 sq. in

Step-by-step explanation:

perimeter = 44 inches

length is half the width + 7

a = length

b = width

a + a + b + b = 44

a + b = 22

a + b/2 = 7

b + b/2 + 7 = 22

b + b/2 = 15

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b= 10

area = a x b

area = 120 square inches

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3 years ago
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Lori has 18 new stamps to add to her collection. She displays the stamps on pages of an album in groups of either 3, 6, or 9 sta
NeTakaya
To do groups of 9, she could make 2 rows of 9. To do 3, she could do 6 rows of 3. Last, to do 6 she could do 3 rows of 6. :)
6 0
3 years ago
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For their homecoming​ parade, the students of​ U-Math have created a colorful​ banner, 57 meters in​ length, that is made of two
BartSMP [9]

Answer:

Length\ of\ the\ long\ piece=40\ meters\\\\Length\ of\ the\ short\ piece=17\ meters

Step-by-step explanation:

Let be "s" the length in meters of the short piece and "l" the lenght in meters of the long piece.

Set up a system of equations:

\left \{ {{s+l=57} \atop {s=l-23}} \right.

Apply the Substitution Method to solve the system. Substitute the second equation into the first equation and solve for "l":

(l-23)+l=57\\\\2l=80\\\\l=\frac{80}{2}\\\\l=40

Susbstitute the value of "l" into the second equation in order to find the value of "s". This is:

s=40-23\\\\s=17

6 0
3 years ago
The perimeter of a rectangle must be less than 156 feet. If the length is known to be 66 feet, find the range of possible widths
balu736 [363]

x = perimeter

x<156

length = 66

so, in order to calculate perimeter you need to add two lengths and two widths

so

156 (perimeter) - 2 (66) = two widths

156 - 132 = 24 (remember this number is two widths added together)

so 24 twice the width SO 12 would be the number that the width can't be larger than

the width has to be less than 12

w < 12

5 0
3 years ago
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