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il63 [147K]
3 years ago
12

A party mix has 8 ounces of pretzels,3 ounces of mini marshmallows, and 6 ounces of nuts. how many ounces of nuts are there for

every ounce of pretzels?
Mathematics
1 answer:
Mars2501 [29]3 years ago
3 0
Hey! Sorry that no one has answered your question in 4 days. But anyways, to do this, we need to simplify the problem a little. The mini marshmallows are unneeded, so we don't even have to think about them. Do do this, all you need to do is divide the 6 ounces of nuts and the 8 ounces of pretzels, or 6 / 8, to get 0.75.
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Direction: True or False
Goshia [24]

Answer:

<u>False </u>Any three points are always coplanar

<u>False </u>Two points are always collinear

<u>False </u>Two planes intersect at a point

Read explanations, as the answer to these questions, is subjective.

Step-by-step explanation:

The definition of coplanar is; figures that exist on the same plane. Any three points might not always be colinear, as some points might exist on one plane, but other points could exist on other planes. To visualize this phenomenon, refer to the attached image. Two points could be on the red plane, but the third could be on the green. Therefore, while there are three points, not all of them exist on the same plane. However, another plane can be constructed to connect these points, bear in mind certain problems might specifically indicate that three points are not coplanar, therefore, the answer is false.

The definition of collinear is existing on the same line. This statement is a little subject, it can be both true and false depending on the way one looks at it. A line can be drawn to connect any two points, one only needs two points to determine a line. So technically two points are always collinear. However, it also depends on the circumstance. Certain geometry problems might specifically indicate that two points are not collinear. Thus, it really depends on the context. Therefore, the answer is technically false.

Two planes usually intersect on a line. To understand this, please refer to the image attached. Tehcnailly, if a corner of one plane intersects another, then one can state that the plane intersects on a point, but typically, planes intersect on lines. Therefore, technically the answer to this problem is false, as two planes usually intersect on a line.

Images credits: Geogebra

8 0
3 years ago
Read 2 more answers
The lengths of the sides of a triangle are 2x+1, 3x-2, and 4x-5. what is the perimeter in terms of x
STALIN [3.7K]

Answer:

Step-by-step explanation:

2X + 1 + 3X - 2 + 4X - 5 = 180

9X - 6 = 180

9X = 174

9   =   174

ـــــــــــــــــــــ

9         9

X = 19.333

8 0
3 years ago
Pls help I dont know how to do this​
german

Answer:

  • 1. CE = 63
  • 2. x = 16

Step-by-step explanation:

Use proportions to solve.

Corresponding sides have same ratio.

<u>Question 1</u>

  • DE/EG = CE/EF
  • (6x + 3)/17 = (8x - 1)/21
  • 21(6x + 3) = 17(8x - 1)
  • 126x + 63 = 136x - 17
  • 10x = 80
  • x = 8
  • CE = 8*8 - 1
  • CE = 63

<u>Question 2</u>

  • KM/MD = KZ/ZH
  • (x + 8)/21 = 32/28
  • x + 8 = 21*8/7
  • x + 8 = 24
  • x = 24 - 8
  • x = 16
5 0
3 years ago
What radius of a circle is required to inscribe a regular hexagon with an area of 210.44 cm2 and an apothem of 7.794 cm
alekssr [168]
We know that

[area of a regular hexagon]=6*[area of one <span>equilateral triangle]
</span>210.44=6*[area of one equilateral triangle]
[area of one equilateral triangle]=210.44/6-----> 35.07 cm²

[area of one equilateral triangle]=b*h/2
h=7.794 cm
b=2*area/h------> b=2*35.07/7.794------>b= 9 cm

the length side of a regular hexagon is 9 cm
<span>applying the Pythagorean theorem
</span>r²=h²+(b/2)²------>r²=7.794²+(4.5)²------> r²=81--------> r=9 cm

<span>this last step was not necessary because the radius is equal to the hexagon side------> (remember the equilateral triangles)
</span>
the answer is
the radius is 9 cm
8 0
3 years ago
Will mark brainlest help me please​
Allushta [10]

Answer:

  • no le entiendo por qué estás en inglés

7 0
3 years ago
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