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il63 [147K]
3 years ago
12

A party mix has 8 ounces of pretzels,3 ounces of mini marshmallows, and 6 ounces of nuts. how many ounces of nuts are there for

every ounce of pretzels?
Mathematics
1 answer:
Mars2501 [29]3 years ago
3 0
Hey! Sorry that no one has answered your question in 4 days. But anyways, to do this, we need to simplify the problem a little. The mini marshmallows are unneeded, so we don't even have to think about them. Do do this, all you need to do is divide the 6 ounces of nuts and the 8 ounces of pretzels, or 6 / 8, to get 0.75.
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A plumber charges a base fee of $ 60, and then each hour of work costs $ 15. Yesterday Joe hired the plumber to fix his sink, at
lutik1710 [3]

Answer:

12 hours

Step-by-step explanation:

Step one:

given data

base fee= $60

charge per hour= $15

let the number of hours the plumber work be x

the linear function for the charge is the equation of line.

that is y=mx+c

Step two:

given that y=$240

240=15x+60

240-60=15x

180=15x

divide both sides by 15 we have

x=180/15

x=12

<u>The number of hours is 12</u>

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Solve the system of equations by finding the reduced row echelon form of the augmented matrix. Write the solutions for x and y i
Gwar [14]

Answer:

The solutions for the given system of equations are:

\left \{ {{x=-5} \atop {y=12-4z}} \right.

Step-by-step explanation:

Given the equation system:

\left \{ {{3x+y+4z=-3} \atop {-x+y+4z=17}} \right.

We obtain the following matrix:

\left[\begin{array}{cccc}3&1&4&-3\\-1&1&4&17\end{array}\right]

<u>Step 1:</u> Multiply the fisrt row by 1/3.

\left[\begin{array}{cccc}1&\frac{1}{3} &\frac{4}{3}&-1\\-1&1&4&17\end{array}\right]

<u>Step 2:</u> Sum the first row and the second row.

\left[\begin{array}{cccc}1&\frac{1}{3} &\frac{4}{3}&-1\\0&\frac{4}{3} &\frac{16}{3}&16\end{array}\right]

<u>Step 3:</u> Multiply the second row by 3/4.

\left[\begin{array}{cccc}1&\frac{1}{3} &\frac{4}{3}&-1\\0&1 &4&12\end{array}\right]

<u>Step 4:</u> Multiply the second row by -1/3 and sum the the first row.

\left[\begin{array}{cccc}1&0 &0&-5\\0&1 &4&12\end{array}\right]

The result of the reduced matrix is:

\left \{ {{x=-5} \atop {y+4z=12}} \right.

This is equal to:

\left \{ {{x=-5} \atop {y=12-4z}} \right.

These are the solutions for the system of equations in terms of z, where z can be any number.

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Answer:

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Step-by-step explanation:

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