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Maslowich
4 years ago
12

a triangle has side measuring 8 inches and 12 inches if x represents the length in inches o the third side which inequality give

s the range of possible values for x
Mathematics
1 answer:
TEA [102]4 years ago
3 0

Triangle inequality theorem states that the sum of the lengths of two sides of a triangle will always be more than the length of the third side.

Given the two sides of the triangle as 8 inches and 12 inches.

There sum would be 8 + 12 = 20 inches.

So, according to the theorem:

Sum of side measureing 8 inches and 12 inches must be more than x.

So, 8 + 12 > x.

20 > x

Therefore, x < 20.

So, x must be less than 20 inches.

Hope this helps you!

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$12,400 is invested, part at 6% and the rest at 5%. If the interest earned from the amount invested at 6% exceeds the interest e
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Answer:  $10881.81 is invested at 6% and $1518.18 is invested at 5%.

Step-by-step explanation:

Since we have given that

Amount invested = $12400

Rate of interest for first part = 6%

Rate of interest for second part = 5%

Let the amount invested for 6% be 'x'.

Let the amount invested for 5% be 'y'

According to question, we get that

0.06x-0.05y=577\\\\x+y=12400\\\\\implies x=12400-y

So, it becomes,

0.06(12400-y)-0.05y=577\\\\744-0.06y-0.05y=577\\\\-0.11y=577-744\\\\-0.11y=-167\\\\y=\dfrac{167}{0.11}\\\\y=1518.18

x=12400-y=12400-1518.18=$10881.81

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Find the sum of 1/3 + 2/3 + 3/3 + ...12/3
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Step-by-step explanation:

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According to a survey, 10% of Americans are afraid to fly. Suppose 1100 Americans are sampled. a) What is the probability that 1
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b) 0.00%

c) 1.54%

Step-by-step explanation:

According to the survey, 10% of Americans are afraid to fly.

This means p=0.10 and q=1-0.10=0.90.

If 1100 Americans are sampled, then the sample size is n=1100 .

The mean of the distribution is \mu=np.

This means \mu=1100\times 0.10=110

The standard deviation is \sigma=\sqrt{npq}

We substitute the values to get:

\sigma=\sqrt{1100\times 0.1\times 0.9}=9.95

a) We want to find the probability that 121 or more Americans in the survey are afraid to fly.

We first apply the continuity correction factor to get: P(X\ge121)=P(X\:>\:121-0.5)\\P(X\ge121)=P(X\:>\:120.5)

We now convert to Z-scores to get:

P(X\:>\:120.5)=P(z\:>\:\frac{120.5-110}{9.95})=1.06\\

From the standard normal distribution table P(z>1.06)=0.1446

As a percentage, the probability is 14.46%

b) We want to find the probability that 165 or more Americans in the survey are afraid to fly.

We apply the CCF to get:

P(X\ge165)=P(X\:>\:165-0.5)\\P(X\ge165)=P(X\:>\:164.5)

We convert to z-scores:

P(X\:>\:164.5)=P(z\:>\:\frac{164.5-110}{9.95})=5.48

From the normal distribution, P(z>164.5)=0

c)  First, 8% of 1100 is 88.

We want to find the probability that 88 or less Americans in the survey are afraid to fly.

We apply the CCF to get:

P(X\le88)=P(X\:

We convert to z-scores:

P(X\:

From the normal distribution, P(z>\:-2.16)=0.0154

As a percentage, we get 1.54%

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3 years ago
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