Answer:
So first lets find g(-1)
so we plug in the answers:
-2 * -1 ^2 -4
-2*1-4 = -2-4 =
-6
Now lets solve for f(-2)
-2^2-3
4-3=1
-6+1 = 5
3*5 = 15
Im getting answer of 15 but it shows -15 or something, so I dont know if I got it wrong or if its like a dash then the answer.
Answer: C）14,000 + 5,600 + 70 + 21
Step-by-step explanation:
2813=2000+800+10+3
2000*7=14000
800*7=5600
10*7=70
3*7=21
i hope it help ο(=•ω＜=)ρ⌒☆
A and C are the correct answers
Answer:
Step-by-step explanation:
The local minimum of function is an argument x for which the first derivative of function g(x) is equal to zero, so:
g'(x)=0
g'(x)=(x^4-5x^2+4)'=4x^3-10x=0
x(4x^2-10)=0
x=0 or 4x^2-10=0
4x^2-10=0 /4
x^2-10/4=0
x^2-5/2=0
[x-sqrt(5/2)][x+sqrt(5/2)]=0
Now we have to check wchich argument gives the minimum value from x=0, x=sqrt(5/2) and x=-sqrt(5/2).
g(0)=4
g(sqrt(5/2))=25/4-5*5/2+4=4-25/4=-9/4
g(-sqrt(5/2))=-9/4
The answer is sqrt(5/2) and -sqrt(5/2).
