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3 years ago

How to you express area of each square as monomial

1 answer:

6 0

The area of a rectangle (including squares) is defined as length times width or the equation:

A=l×w

However a square has the special property where length equals width which is represented by this equation:

l=w

So replace one of the variables with the other to get this new equation:

l×w=A
(w)×w=A
w^2=A

Often times for square the variable is represented as an s so:

s^2

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What is the answer 0,12km² a m² show work

seraphim [82]

Answer:

120 000 m^2

Step-by-step explanation:

I ASSUME you're being asked to convert from km^2 to m^2.

For this you need to identify the conversion rate, which is 1 000 000 m^2 / 1 km ^2. Multiply by the thing you're converting from and cancel the units.

(1 000 000 m^2 / 1 km ^2) x 0,12 km^2 = 120 000 m^2 (the km^2 cancels out, leaving you only with your target unit of m^2)

8 0

2 years ago

Read 2 more answers

Junior has a recipe that uses 1 3/4 cups of brown sugar and 3 1/3 cups of flour to make 18 muffins. He has a total of 10 cups of

Furkat [3]

54 muffins because if you take both your given fraction find the nearest common denominator which is 3 4/12 divide the 4 and 12 to get 3 than divide by 0.10 than divided by a whole 10 which got me 3.03 etc.

Round it see how many times it can go into 10 3 times than multiply it by 18.

8 0

3 years ago

Use the identity (x2+y2)2=(x2−y2)2+(2xy)2 to determine the sum of the squares of two numbers if the difference of the squares of

fomenos

Answer:

The sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is <u>169</u>

Step-by-step explanation:

Given : the difference of the squares of the numbers is 5 and the product of the numbers is 6.

We have to find the sum of the squares of two numbers whose difference and product is given using given identity,

$(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2$

Since, given the difference of the squares of the numbers is 5 that is $(x^2-y^2)^2=5$

And the product of the numbers is 6 that is $xy=6$

Using identity, we have,

$(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2$

Substitute, we have,

$(x^2+y^2)^2=(5)^2+(2(6))^2$

Simplify, we have,

$(x^2+y^2)^2=25+144$

$(x^2+y^2)^2=169$

Thus, the sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is 169

5 0

3 years ago

Read 2 more answers

Help<br> I dont know the answer im not very smart

Dahasolnce [82]

The domain of G is 4 and the range of G is 9 (domain=x, range=y :))

8 0

2 years ago

Help me to do this question

zysi [14]

Answer:

c1) adjacent

c2) not adjacent

c3) adjacent

c4) not adjacent

c5) adjacent

c6) not adjacent

d1) 20°

Complement: 90° - 20° = 80°

Supplement: 180° - 20° = 160°

d2) 77°

Complement: 90° - 77° = 13°

Supplement: 180° - 77° = 103°

d3) 101°

Complement: doesn't have a complement.

Supplement: 180° - 101° = 79°

d4) 90°

Complement: 90° - 90° = 0°

Supplement: 180° - 90° = 90°

d5) 96°

Complement: doesn't have a complement

Supplement: 180° - 96° = 84°

d6) x

Complement: 90° - x

Supplement: 180° - x

d7) y

Complement: 90° - y

Supplement: 180° - y

7 0

3 years ago