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Pani-rosa [81]
3 years ago
6

A population of 100 frogs increases at an annual rate of 22%. How many frogs will there be in 5 years? Write an expression to re

present the equivalent monthly population increase rate.
Mathematics
1 answer:
gizmo_the_mogwai [7]3 years ago
6 0
Exponential growth of the form:

F=Ar^t

F=100(1.22)^t

F(5)=100(1.22)^5

F(5)=270.27

F(5)=270 to the nearest frog...

....

1.22=r^12

r=1.22^(1/12)

F=100(1.22^(1/12)^t)

F=100(1.22^(t/12))  now it will produce monthly populations...

Say we did the same as before but instead of 5 years you have 60 months...

F(60)=100(1.22^(60/12))

F(60)=270 to the nearest frog... :P 
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