The answer is 25 but i can't exactly show how
The rubric of 150 is the sim of the square but the area would be 59 which would equal to the amount of 50
Divide by 7.
... |-7x -3| = 3
Unfold to two equations.
... -3 = -7x -3 . . . . . the content of the absolute value is negative
... 0 = -7x . . . . . . . . add 3
... 0 = x . . . . . . . . . . divide by -7
and
... 3 = -7x -3 . . . . . . the content of the absolute value is positive
... 6 = -7x . . . . . . . . add 3
... -6/7 = x . . . . . . . . divide by -7
The solutions are ...
... x = -6/7 or x = 0
_____
Many graphing programs will happily tell you the locations of x- and y-intercepts, so it is convenient to rewrite the equation so its value is zero at the solution points. We can do that by subtracting the right side constant to get ...
... 7|-7x -3| -21 = 0
<span>3x</span>² <span>- 8x -3 = 3x</span>² - 9x + x - 3 =
= 3x² - 9x + x - 3 = 3x* ( x - 3) + 1* (x - 3) =
= 3x * (x - 3) + 1 * (x - 3) = (3x + 1) (x - 3)
Answer (3x + 1) (x - 3)
Answer:
![\[=>x\geq 4\]](https://tex.z-dn.net/?f=%5C%5B%3D%3Ex%5Cgeq%204%5C%5D)
Step-by-step explanation:
Given inequality is ![\[−7\geq13−5x\]](https://tex.z-dn.net/?f=%5C%5B%E2%88%927%5Cgeq13%E2%88%925x%5C%5D)
Simplifying:
![\[5x\geq13+7\]](https://tex.z-dn.net/?f=%5C%5B5x%5Cgeq13%2B7%5C%5D)
![\[=>5x\geq20\]](https://tex.z-dn.net/?f=%5C%5B%3D%3E5x%5Cgeq20%5C%5D)
![\[=>x\geq \frac{20}{5}\]](https://tex.z-dn.net/?f=%5C%5B%3D%3Ex%5Cgeq%20%5Cfrac%7B20%7D%7B5%7D%5C%5D)
![\[=>x\geq 4\]](https://tex.z-dn.net/?f=%5C%5B%3D%3Ex%5Cgeq%204%5C%5D)
Hence the solution for the given inequality is represented by ![\[=>x\geq 4\]](https://tex.z-dn.net/?f=%5C%5B%3D%3Ex%5Cgeq%204%5C%5D)
This means that the original inequality will be true only for those values of x which are greater than or equal to 4.