2 answers:
Answer:

Step-by-step explanation:
This question is on rules of rational exponential
where the exponential is a fraction, you can re-write it using radicals where the denominator of the fraction becomes the index of the radical;
<u>General expression </u>
![a^\frac{1}{n} =\sqrt[n]{a}](https://tex.z-dn.net/?f=a%5E%5Cfrac%7B1%7D%7Bn%7D%20%3D%5Csqrt%5Bn%5D%7Ba%7D)
Thus ![\sqrt[3]{x} =x^\frac{1}{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%7D%20%3Dx%5E%5Cfrac%7B1%7D%7B3%7D)
<u>Applying the same in the question </u>
![\sqrt[3]{x^5y} =x^\frac{5}{3} y^\frac{1}{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E5y%7D%20%3Dx%5E%5Cfrac%7B5%7D%7B3%7D%20y%5E%5Cfrac%7B1%7D%7B3%7D)
=
Answer: Second option

Step-by-step explanation:
By definition we know that:
![a ^{\frac{m}{n}} = \sqrt[n]{a^m}](https://tex.z-dn.net/?f=a%20%5E%7B%5Cfrac%7Bm%7D%7Bn%7D%7D%20%3D%20%5Csqrt%5Bn%5D%7Ba%5Em%7D)
In this case we have the following expression
![\sqrt[3]{x^5y}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E5y%7D)
Using the property mentioned above we can write an equivalent expression for ![\sqrt[3]{x^5y}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E5y%7D)
![\sqrt[3]{x^5y} = (x^5y)^{\frac{1}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E5y%7D%20%3D%20%28x%5E5y%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)

Therefore the correct option is the second option
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