<img src="https://tex.z-dn.net/?f=5%20%2B%204%20-%20%28%205%20-%20%286%20-%205%29%29" id="TexFormula1" title="5 + 4 - ( 5

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Marat540 [252]

3 years ago

5))" alt="5 + 4 - ( 5 - (6 - 5))" align="absmiddle" class="latex-formula">
I don't know how to solve this?

Mathematics

2 answers:

Ket [755]3 years ago

8 0

(6-5)=1 (5-1)=4 5+4=9 9-4=5

Korolek [52]3 years ago

8 0

Answer:

Answer is 5

Step-by-step explanation:

PEMDAS Start with the parenthesis. Make sure you do the deepest parenthesis first. 6 - 5 is 1. Then you do 5 - (1) which is 4.

Last step is 5 + 4 - 4, and -4 cancels out 4 so the final answer is 5

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The Bayer family just left the local pet store with Rover, their new family dog. The pet store owner told the Bayer family that

anyanavicka [17]

Answer:

A. Complete table below

B. Graph is attached below

C. y = 7x - 10

D. 60 pounds.

Step-by-step explanation:

We are given that, Bayer would grow at an average rate of 7 pounds per month.

So, in order to complete the table, we will add 7 to the weights column.

Part A: Thus, we get the following table.

Age, in months 2, 3, 4, 5, 6, 7, 8

Weight, in pounds 4, 11, 18, 25, 32, 39, 46.

Part B: Since, we have the ordered pairs (x,y) given by,

(2,4), (3,11), (4,18), (5,25), (6,32), (7,39) and (8,46).

The graph is shown below.

Part C: Taking any two pairs say (2,4) and (3,11).

We get the slope is, $\frac{11-4}{3-2}$ i.e. slope is 7.

Then, y = mx + b gives, 4 = 7×2 + b i.e. b = 4-14 i.e. b = -10.

Hence, the linear model is given by 'y=7x-10', where x is the age(in months) and y is the weight(in pounds).

Part D: Now, we want to find the weight when Bayer is one year old.

Since, we have that, Bayer is already two months old.

So, we need to find weight when Bayer is 10 months old.

i.e. y=7x-10 ⇒ y = 7×10-10 ⇒ y = 70-10 ⇒ y=60

Hence, Bayer will be 60 pounds when he is one year orld.

4 0

3 years ago

A 20-ounce bag of potato chips costs $3.80. What is the unit rate of the chips?

melisa1 [442]

To find the unit rate you would need to find the cost per ounce of potato chips. To find this you would simply divide. $3.80/20 = .19

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Hope this helps! :)

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3 years ago

Find f(-3) for f(x) = 4(2)^x O A. -32 O B. 1/2 O C. -24 O D. 1/8

V125BC [204]

Answer:

B. 1/2

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Functions

Function Notation

Step-by-step explanation:

Step 1: Define

Identify

f(x) = 4(2)ˣ

Step 2: Evaluate

Substitute in x [Function f(x)]: f(-3) = 4(2)⁻³
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3 years ago

What is the missing length? 10.2 cm a area=51 cm2

Aleksandr [31]

Answer:

Step-by-step explanation

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3 years ago

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4. Mr. Perez's science students conducted a wildlife count in the local forest. The results of their count are shown in the tabl

Cerrena [4.2K]

Circle graphs are used to display the relationship between variables using a complete circle

The angle measures of the sections are 180 degrees, 72 degrees, 72 degrees and 36 degrees, respectively.

The count of the animals are given as:

Squirrel = 25
Rabbit = 10
Deer = 10
Raccoon = 5

The total count of animals is:

$\mathbf{Total = 25 + 10 +10 + 5}$

$\mathbf{Total = 50}$

The angle measure of each section is then calculated using:

$\mathbf{Angle = \frac{Animal \times 360}{Total}}$

So, we have:

$\mathbf{Squirrel = \frac{25 \times 360}{50} }$

Simplify the numerator

$\mathbf{Squirrel = \frac{9000}{50} }$

Divide

$\mathbf{Squirrel = 180}$

$\mathbf{Rabbit= \frac{10\times 360}{50} }$

Simplify the numerator

$\mathbf{Rabbit= \frac{3600}{50} }$

Divide

$\mathbf{Rabbit= 72}$

$\mathbf{Deer= \frac{10\times 360}{50} }$

Simplify the numerator

$\mathbf{Deer= \frac{3600}{50} }$

Divide

$\mathbf{Deer= 72}$

Lastly, we have:

$\mathbf{Raccoon= \frac{5\times 360}{50} }$

Simplify the numerator

$\mathbf{Raccoon= \frac{1800}{50} }$

Divide

$\mathbf{Raccoon= 36}$

Hence, the angle measures of the sections are 180 degrees, 72 degrees, 72 degrees and 36 degrees, respectively.

See attachment for the circle graph