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Marat540 [252]
2 years ago
9

5))" alt="5 + 4 - ( 5 - (6 - 5))" align="absmiddle" class="latex-formula">
I don't know how to solve this?​
Mathematics
2 answers:
Ket [755]2 years ago
8 0
(6-5)=1 (5-1)=4 5+4=9 9-4=5
Korolek [52]2 years ago
8 0

Answer:

Answer is 5

Step-by-step explanation:

PEMDAS Start with the parenthesis. Make sure you do the deepest parenthesis first. 6 - 5 is 1. Then you do 5 - (1) which is 4.

Last step is 5 + 4 - 4, and -4 cancels out 4 so the final answer is 5

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Write a doubles fact to find the sum 3+2
valentina_108 [34]

Answer:

5 or -5

Step-by-step explanation:

3+2=5

-1(3+2)=-5

3 0
3 years ago
Question 17 please help
kramer
\sqrt{9x^2} / \sqrt{18y^2}
after taking sqrt both side

3x/\sqrt{9*2y^2}

3x/3y√2
x/√2y
multiply both denomenator and numerator by√2
√2x/2y

Answer is A

8 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B-8%2F27%7D%20%3D%20-2%2F3" id="TexFormula1" title="\sqrt[3]{-8/27} = -2/3" al
sasho [114]
The equation is true because both sides are identical.
5 0
3 years ago
Help#3 plus plus plus need this
gayaneshka [121]
Wouldn't it be -54. Because when you subtract 5-59 you get a negative number... IT WOULD BE FREEZING THERE!!! I HOPE THIS HELPED
3 0
3 years ago
Read 2 more answers
Find the area of the region shaded in green. Use 3.14 to approximate pi.
8090 [49]

Answer:

254 cm² (to 3 s.f.)

Step-by-step explanation:

Area of shaded region

= area of large circle -area of smaller circle

\boxed{area \: of \: circle = \pi {r}^{2} }

Radius of large circle= 15cm

Radius of smaller circle= 12cm

Area of shaded region

= π(15²) -π(12²)

= 225π -144π

= 81π

= 81(3.14)

= 254.34

= 254 cm² (3 s.f.)

3 0
2 years ago
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