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3 years ago

Which equation is y= 2x ^2 - 8x +9 rewritten in vertex form.

1 answer:

7 0

y= 2x ^2 - 8x +9

y = a(x - h)2 + k, where (h, k) is the vertex of the parabola
so
y= 2x ^2 - 8x + 9
y= 2x ^2 - 8x + 8 + 1
y = 2(x^2 - 4x - 4) + 1
y = 2(x - 2)^2 + 1 ....<---------vertex form

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Step-by-step explanation:

First, factorize the number 3,240:

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Now consider the fraction

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If k = 10, then

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For all k < 10, the fraction tex]\dfrac{3,240}{k}[/tex] is not a square number (this follows from factorization).

Or you can simply check the values of the fraction for all k < 10:

k = 1, $\dfrac{3,240}{1}=3,240$ is not a square number;
k = 2, $\dfrac{3,240}{2}=1,620$ is not a square number;
k = 3, $\dfrac{3,240}{3}=1,080$ is not a square number;
k = 4, $\dfrac{3,240}{4}=810$ is not a square number;
k = 5, $\dfrac{3,240}{5}=648$ is not a square number;
k = 6, $\dfrac{3,240}{6}=540$ is not a square number;
k = 7, $\dfrac{3,240}{7}$ is not a square number;
k = 8, $\dfrac{3,240}{8}=405$ is not a square number;
k = 9, $\dfrac{3,240}{9}=360$ is not a square number.

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