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Furkat [3]
3 years ago
6

Ashley has 20 pieces of candy in a bag: 2 mint sticks, 4 jelly treats, and 14 fruit tart chews. If she eats one piece every 8 mi

nutes, what is the probability her first two pieces will both be jelly treats?
Mathematics
1 answer:
AleksAgata [21]3 years ago
3 0
The probability that her first treat is jelly is 4/20. Since she eats the candy and does not replace it, the probability the second treat is jelly would be 3/19 (1 less jelly and 1 less total candies). You would then multiply (4/20) by (3/19). That is your answer.
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EFGH is a rhombus. Given EG = 16 and FH = 12, what is the length of one side of the rhombus?
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<u>Answer</u>

= 10


<u>Explanation</u>

EG is one of the diagonals of the rhombus and the other diagonal is FH.

EG = 16 and FH = 12

The diagonals of a rhombus meet at 90°

From this information we can form a right triangle with legs (16/2)=8 and (12/2)=6

The hypotenuse of this triangle is the side of the rhombus.

Using the pythagorean theorem;

L² = 6²+8²

Where L is the length of the rhombus.

L² = 6²+8²

L = √36+64

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matrenka [14]

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One manner to check it the usage of the given probabilities:

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Step-by-step explanation:

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The length of a shadow of a building is
timofeeve [1]
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