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ehidna [41]
3 years ago
6

Add.

Mathematics
1 answer:
dedylja [7]3 years ago
3 0

Answer:

C. 6x-7

Step-by-step explanation:

4x+2x=6x

(-3)+(-4)=-7

6x-7

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Find the equation of a line that contains the points (4,−1) and (−1,−4). Write the equation in slope-intercept form, using fract
olga_2 [115]

Answer:

y = 3/5x - 17/5

Step-by-step explanation:

slope formula: (y₂ - y₁) / (x₂ - x₁)

First, plug in these values of the two given points.

(-4 - (-1)) / (-1 - 4)

Simplify within the parentheses.

(-4 + 1) / (-1 - 4)

(-3) / (-5)

3/5

This is your slope. Plug this into a standard slope-intercept equation: y = mx + b

To find b, we want to plug in a value that we know is on this line: in this case, I will use the second point (-1, -4). Plug in the x and y values into the x and y of the standard equation.

-4 = 3/5(-1) + b

Multiply.

-4 = -3/5 + b

Add 3/5 to both sides. -- To add it easier, <em>convert 4 to a have a denominator of 5</em>.

-20/5 = -3/5 + b

-20/5 + 3/5 = b

-17/5 = b

Now, plug this into your standard equation.

y = 3/5x - 17/5

Check this equation by plugging in the <em>other point you did not use</em> (4, -1)

-1 = 3/5(4) - 17/5

-1 = 12/5 - 17/5

-1 = -5/5

-1 = -1

Your answer is correct!

Hope this helps!

6 0
3 years ago
Trinomials can be factored into two sets of binomials. Always, sometimes, or never?
MAXImum [283]
Trinomials are polynomials that contain three(3) terms. A trinomial can sometimes be factored into two binomial and sometimes, it cannot be factored at all. In factoring, the each term in the trinomial equation affect the capability of it to be factored. Thus, trinomial are can be sometimes be factored into two sets of binomials.
5 0
3 years ago
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liberstina [14]

Answer:

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Step-by-step explanation:

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3 years ago
Find the volume of the square prism measuring 6km along each edge of the base and 5 km tall (no units)
KiRa [710]

Answer:

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Step-by-step explanation:

7 0
3 years ago
8. A home security system has a pad with 9 digits (1 to 9). Find the number of possible 5-digit pass codes:
nikdorinn [45]

Answer:

a. 59049

b. 15120

Step-by-step explanation:

<u>a. If digits can be repeated:</u>

  • There are 9 possible numbers for each digit

That is:  possible 5-digit pass codes are 9×9×9×9×9=9^{5}=59049

<u>b. If digits cannot be repeated.</u>

There is

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  • 7 possibility for the third digit
  • 6 possibility for the fourth digit
  • 5 possibility for the fifth digit

That is:  possible 5-digit pass codes are 9×8×7×6×5=15120

5 0
3 years ago
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