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2 years ago

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1 answer:

5 0

Answer: Cylinder 1 - 25.1327412283 cubic cm
Cylinder 2 - 100.5309469149 cubic cm
Cylinder 3 - 226.1946710585 cubic cm

For each of the cylinders, we will need to use the same formula, h(pi(r squared)).

Cylinder 1 - 8(pi(1 squared)). 1 squared = 1. pi × 1 = 3.1415926536. 3.1415926536 × 8 = 25.1327412283 cubic cm.

Cylinder 2 - 8(pi(2 squared)). 2 squared = 4. 4 × pi = 12.5663706144. 12.5663706144 × 8 = 100.5309469149 cubic cm.

Cylinder 3 - 8(pi(3 squared)). 3 squared = 9. 9 × pi = 28.2743338823. 28.2743338823 × 8 = 226.1946710585 cubic cm.

- Hope it helps!

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Five digit serial numbers for a product are to be made using letters and/or numbers, e.G. JGR29. The serial number could have al

S_A_V [24]

Answer:

1,404,000 serial numbers can be made

Step-by-step explanation:

For the five digit serial numbers, since all letters and all numbers could be used, then we can use 26 letters (A,B,C,...Z) and 10 numbers (0,1,2,...9).

Now, say the letters and numbers are to occupy the labeled spaces below

_ _ _ _ _

1 2 3 4 5

(NOTE: Spaces 1,2,3 are to be occupied by any of the 26 letter while spaces 4 and 5 are to be occupied by any of the 10 numbers)

For space 1, there are 26 possibilities

For space 2, there will be (26 -1 ) 25 possibilities (since repetition of characters is NOT allowed)

For space 3, there will be (26-2) 24 possibilities (since repetition of characters is NOT allowed)

For space 4, we have 10 possibilities

and for space 5, we (10-1) 9 possibilities (since repetition of characters is NOT allowed)

Therefore, the number of serial numbers that can be made is

26 × 25 × 24 × 10 × 9 = 1404000

Hence, 1,404,000 serial numbers can be made

Using permutation, nPr = n!/(n-r)!

For the letters,

n is the total number; n = 26

and r is the number of available spaces, r = 3

For the numbers,

n = 10

r = 2

Then, we get

26P3 × 10P2

26!/(26-3)! × 10!/(10-2)!

26!/23! × 10!/8!

15600 × 90 = 1404000

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2 years ago

The length of a rectangle is 3 times longer than its width. If the area of the rectangle is 24 square inches, then what is the p

NikAS [45]

Answer: The answer is 16√2 cm.

Step-by-step explanation: Given that there is a rectangle with length 3 times than its width. We are to find the perimeter of the rectangle.

Let 'w' represents the width of the rectangle.

Then, its length will be 3w.

Also, area of the rectangle = 24 square inches.

Therefore,

$3w\times w=24\\\\\Rightarrow 3w^2=24\\\\\Rightarrow w^2=8\\\\\Rightarrow w=2\sqrt 2.$

So, width = 2√2 inches and length = 6√2 inches.

Thus, perimeter of the rectangle = 4√2 + 12√2 = 16√2 cm.

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2 years ago

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PLEASE HELP!! if sec x=5/3 what is the value of b? NL=20 LM=3b angle of L is x degrees.

Readme [11.4K]

Answer:

a. b=4

Step-by-step explanation:

$\sec \theta =\dfrac{1}{\cos \theta} = \dfrac{Hypotenuse}{Adjacent}$

From the attached triangle drawn below:

NL=20, LM=3b, $\angle L=x^\circ$

$\sec x =\dfrac{20}{3b}$

Since we are told that:

$\sec x =\dfrac{5}{3}\\$Then:\\\dfrac{20}{3b} =\dfrac{5}{3}\\$Cross multiply\\5 \times 3b =20 \times 3\\15b=60\\$Divide both sides by 15\\15b \div 15 =60 \div 15\\b=4$

The correct option is A.

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2 years ago

A radio transmission tower is 170 feet tall. How long should a guy wire be if it is attached 15 feet from the top and makes a 27

MatroZZZ [7]

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2 years ago

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Kryger [21]

The answer will be D

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