Answer:
B
$2.730 divided by 6 equals 455
$5,496 divided by 12 equals 458
458-455=3 so the answer is B
The zeros of the function f(x) = x^3 + 3x^2 + 2x are x = 0, x = -1 and x = -2
<h3>How to determine the zeros of the function?</h3>
The function is given as:
f(x) = x^3 + 3x^2 + 2x
Factor out x in the above function
f(x) = x(x^2 + 3x + 2)
Set the function to 0
x(x^2 + 3x + 2) = 0
Factorize the expression in the bracket
x(x + 1)(x + 2) = 0
Split the expression
x = 0, x + 1 = 0 and x + 2 = 0
Solve for x
x = 0, x = -1 and x = -2
Hence, the zeros of the function f(x) = x^3 + 3x^2 + 2x are x = 0, x = -1 and x = -2
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sorry just want some points :)
So far, there is no units we can see becaus we have no context what this is trying to find
so
use the distributive property which goes like this: a(b+c)=ab+ac
so
first distribute
6(60-r)=6(60)+6(-r)=360-6r
now we have
15r+360-6r=
15r-6r+360=
9r+360
there are no units associated with the expression