Answer:
Step-by-step explanation:
If Oliver randomly selects 200 switches for a check of a recently produced lot, the probability of selecting exactly 1 defective switch is 0.360, the probability of selecting exactly 2 defective switches is 0.144, the probability of selecting exactly 3 defective switches is 0.038, the probability of selecting exactly 4 defective switches is 0.008, and the probability of selecting exactly 5 defective switches is 0.001.
X: Number of defective switches that Oliver selects, Assuming the probability of Oliver selecting 6 or more defective switches is 0.
The probability distribution of X is as follows:
X 0 1 2 3 4 5 >6
P(X) 0.449 0.360 0.144 0.038 0.008 0.001 0
